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anonymous

  • 5 years ago

how do you simplify 2sin^2(x/2)?

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  1. amistre64
    • 5 years ago
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    looks pretty simple as is to me :) what are ya going for?

  2. amistre64
    • 5 years ago
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    2(1-cos^2(x/2)) = 2 - 2cos^2(x/2) doesnt seem to help..

  3. anonymous
    • 5 years ago
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    i got that, but what do I do next? or is that not right

  4. amistre64
    • 5 years ago
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    it all depends on what your definition of "simplified" means... are we wanting only single exponents?

  5. amistre64
    • 5 years ago
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    err...exponents of 1?

  6. anonymous
    • 5 years ago
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    yes, just one term

  7. amistre64
    • 5 years ago
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    one term it already is, but do you mean like sin(x/2) instead of sin^2(x/2)?

  8. anonymous
    • 5 years ago
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    yes, i believe so

  9. amistre64
    • 5 years ago
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    hmmmm...... we can play around with identites some and see what happens i spose... do you recall the formula for reducing an exponent?

  10. anonymous
    • 5 years ago
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    nope, im so hopless haha

  11. amistre64
    • 5 years ago
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    cos(2a) = cos^2 - sin^2 cos(2a)= 1 - 2sin^2(2a) cos(t) -1 ------- = sin^2(t) 2 try this one

  12. amistre64
    • 5 years ago
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    2(cos(x/2) -1) ------------ = sin^2(x/2) 2

  13. anonymous
    • 5 years ago
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    okay, hold on ne second while i work it out

  14. amistre64
    • 5 years ago
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    .....2sin^2(x/2)

  15. anonymous
    • 5 years ago
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    okay, that worked. i understand that, thanks!

  16. amistre64
    • 5 years ago
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    that needs alittle fixing... cos(x)-1 -------- = sin^2(x/2) 2 thats what it should be before you put it in

  17. amistre64
    • 5 years ago
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    cos(x) - 1 = 2sin^2(x/2)

  18. anonymous
    • 5 years ago
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    ohh, okay, I see it now.

  19. amistre64
    • 5 years ago
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    better? :)

  20. anonymous
    • 5 years ago
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    yupp, thanks a lot!

  21. amistre64
    • 5 years ago
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    to double check, throw in a number and see :)

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