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anonymous
 5 years ago
what is the maximums and minimums of the equation y=2.657x^3 + 1.48x^2 + .2819x + 7.7E14?
anonymous
 5 years ago
what is the maximums and minimums of the equation y=2.657x^3 + 1.48x^2 + .2819x + 7.7E14?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats kinda complicated to figure out you should go to http://www.wolframalpha.com

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if this is a y or f(x) then differentiate it then equaled it to zero and find its roots, that rot will be your max or min point..just plug it into your original equation....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Y'=7.7971X^2 2.96X +.2819.....NOW THIS IS A QUADRATIC EQUATION,.YOU CAN SOLVE FOR THE ROOTS NOW

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is supposed to be a quartic...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no,,, quartic eq starts at say x^4,....cubic is x^3.... quadratic is x^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what do i do after i derive the equation to find the minimums and maximums?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this does start at x^4...... 1.28x4 + 33.36x3 + 323.41x2 + 1384.63x + 2206.60

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hehe look up at your prob here atart at y=x^3 it a cubic eq rt?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait who are you talking to?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0after you done the derivative, the derivative is now a quadratic y'= ...x^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then how do you find the minimums and maximums

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok ..you equate the derivative to zero and find its roots

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that roots will become you max or min of your original equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what is the answer after equating the derivative

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, to find the roots, do you know the quadratic formila?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x=(b+\[\sqrt{?}\]b24ac)2a

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im sorry my pc equation writer does not write well here you a=7.797.....b=2.96...c= .2819

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x=(2.96+\[\sqrt{?}\].0303)/15.594

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0did you get it? the roots are imaginaries...do you know what is imaginary number?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0obviously... a number that's imaginary like i for example or e

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im just asking what are the points (max and min) for my equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no...any square root of a negative number are imaginary number like square root of 1, sqrot of 2, squroot of  numbers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok here the simplest way of geting the derivative roots is to graph the derivative and approximate its roots..did you get what i mean?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Y'=7.7971X^2 2.96X +.2819.....graph this and find its root or zeroes

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0here one root is 0.2819...you plug it in your orig equation y=2.657(.2819)^3 + 1.48(.2819)^2 + .2819(.2819)+ 7.7E14=?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i graph it rt now and found the root x=0.8948 now you can plug it in to your orig prob.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0your max or min y=0.9708296575

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry never mind that root x=.2819 or min y=.02137744667....thats a mistake,, graph it and found that the max or min y=.9708296575
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