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thats kinda complicated to figure out you should go to http://www.wolframalpha.com
if this is a y or f(x) then differentiate it then equaled it to zero and find its roots, that rot will be your max or min point..just plug it into your original equation....
Y'=7.7971X^2 -2.96X +.2819.....NOW THIS IS A QUADRATIC EQUATION,.YOU CAN SOLVE FOR THE ROOTS NOW
this is supposed to be a quartic...
no,,, quartic eq starts at say x^4,....cubic is x^3.... quadratic is x^2
what do i do after i derive the equation to find the minimums and maximums?
this does start at x^4...... -1.28x4 + -33.36x3 + -323.41x2 + -1384.63x + -2206.60
no it doesn't
hehe look up at your prob here atart at y=x^3 it a cubic eq rt?
wait who are you talking to?
after you done the derivative, the derivative is now a quadratic y'= ...x^2
then how do you find the minimums and maximums
ok ..you equate the derivative to zero and find its roots
that roots will become you max or min of your original equation
what is the answer after equating the derivative
ok, to find the roots, do you know the quadratic formila?
im sorry my pc equation writer does not write well here you a=7.797.....b=-2.96...c= .2819
did you get it? the roots are imaginaries...do you know what is imaginary number?
obviously... a number that's imaginary like i for example or e
im just asking what are the points (max and min) for my equation
no...any square root of a negative number are imaginary number like square root of -1, sqrot of -2, squroot of - numbers
ok here the simplest way of geting the derivative roots is to graph the derivative and approximate its roots..did you get what i mean?
Y'=7.7971X^2 -2.96X +.2819.....graph this and find its root or zeroes
here one root is 0.2819...you plug it in your orig equation y=2.657(.2819)^3 + -1.48(.2819)^2 + .2819(.2819)+ 7.7E-14=?
i graph it rt now and found the root x=0.8948 now you can plug it in to your orig prob.
your max or min y=0.9708296575
sorry never mind that root x=.2819 or min y=.02137744667....thats a mistake,, graph it and found that the max or min y=.9708296575