what is the maximums and minimums of the equation y=2.657x^3 + -1.48x^2 + .2819x + 7.7E-14?

- anonymous

what is the maximums and minimums of the equation y=2.657x^3 + -1.48x^2 + .2819x + 7.7E-14?

- jamiebookeater

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- anonymous

thats kinda complicated to figure out you should go to http://www.wolframalpha.com

- anonymous

your welcome

- anonymous

if this is a y or f(x) then differentiate it then equaled it to zero and find its roots, that rot will be your max or min point..just plug it into your original equation....

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## More answers

- anonymous

Y'=7.7971X^2 -2.96X +.2819.....NOW THIS IS A QUADRATIC EQUATION,.YOU CAN SOLVE FOR THE ROOTS NOW

- anonymous

this is supposed to be a quartic...

- anonymous

no,,, quartic eq starts at say x^4,....cubic is x^3.... quadratic is x^2

- anonymous

what do i do after i derive the equation to find the minimums and maximums?

- anonymous

this does start at x^4...... -1.28x4 + -33.36x3 + -323.41x2 + -1384.63x + -2206.60

- anonymous

no it doesn't

- anonymous

it's 2.657x^3.....

- anonymous

hehe look up at your prob here atart at y=x^3 it a cubic eq rt?

- anonymous

wait who are you talking to?

- anonymous

after you done the derivative, the derivative is now a quadratic y'= ...x^2

- anonymous

then how do you find the minimums and maximums

- anonymous

ok ..you equate the derivative to zero and find its roots

- anonymous

that roots will become you max or min of your original equation

- anonymous

what is the answer after equating the derivative

- anonymous

ok, to find the roots, do you know the quadratic formila?

- anonymous

x=(-b+\[\sqrt{?}\]b2-4ac)2a

- anonymous

im sorry my pc equation writer does not write well
here you a=7.797.....b=-2.96...c= .2819

- anonymous

x=(2.96+-\[\sqrt{?}\]-.0303)/15.594

- anonymous

did you get it? the roots are imaginaries...do you know what is imaginary number?

- anonymous

obviously... a number that's imaginary like i for example or e

- anonymous

im just asking what are the points (max and min) for my equation

- anonymous

no...any square root of a negative number are imaginary number like square root of -1, sqrot of -2, squroot of - numbers

- anonymous

ok here the simplest way of geting the derivative roots is to graph the derivative and approximate its roots..did you get what i mean?

- anonymous

Y'=7.7971X^2 -2.96X +.2819.....graph this and find its root or zeroes

- anonymous

here one root is 0.2819...you plug it in your orig equation
y=2.657(.2819)^3 + -1.48(.2819)^2 + .2819(.2819)+ 7.7E-14=?

- anonymous

min y=0.02137744667

- anonymous

i graph it rt now and found the root x=0.8948 now you can plug it in to your orig prob.

- anonymous

your max or min y=0.9708296575

- anonymous

sorry never mind that root x=.2819 or min y=.02137744667....thats a mistake,, graph it and found that the max or min y=.9708296575

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