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anonymous

  • 5 years ago

write as a perfect cube: 64z^6

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  1. anonymous
    • 5 years ago
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    what * what * what = 64?

  2. anonymous
    • 5 years ago
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    what about the z^6

  3. anonymous
    • 5 years ago
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    What is the number first?

  4. anonymous
    • 5 years ago
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    4

  5. anonymous
    • 5 years ago
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    OK (4z )^3 Since we are going to have a power to a power on the z term... You take the 6 and divide by 3 = 2 SO (4z^2)^3

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