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Area = LW
Perimeter = L1 + L2 + 2W
180 = LW
2L(5) + W(5) + L(15) = cost

since 180 = LW, we can say that W = 180/L

that L(15) up there should be W(15)
2L(5) + (180/L)(5) + (180/L)(15) = Cost

10L +900/L + 2700/L = cost

dP = L(2L) - (2L^2+360)(1)
-------------------
L(L)

4L^2 - 2L^2 - 360 2L^2-360
----------------- = ---------
L^2 L^2
I adjusted for my stupidity :)

when the top is 0 we got a min or a max

2(L^2 -180) = 0
L^2 - 180 = 0
L^2 = 180
L = +sqrt(180)

...... lol ..........

i forgot to adjust for all my stupidity lol

it ok you have it i see just a mix up of numbers is all...

L = sqrt(280) :)

W = 280/sqrt(280)
W = sqrt(280) as well, so its a square I guess...

2L(5) + (280/L)(5) + (280/L)(15) = Cost
10L + 900/L + 4200/L = cost

10L^2 + 900 + 4200
------------------ = cost
L

stop me when I get lost :)

10L^2 + 5100
------------ = cost
L
L(20L) - 1(10L^2 + 5100)
----------------------- = cost'
L^2

wait i am confused....it wants to know the dimensions...so why are we looking for cost

yea...

Now figure out how much we need for the most expensive side :)

2(22.58)(5) + 12.40(5) + 12.40(15) =?
2(12.40)(5) + 22.58(5) + 22.58(15)? which is cheaper?

280/L or 280/W doesnt matter, since its just a name for a side..right?

polpak is here.... hell know what I did wrong ;)

hit "post" lol

Thanks figured it out...

Ok cool.

so where did I miss it?

I can't tell, but you have a lot of cost functions and none of them look the same as the one I have.

:) they are similar.... I was just going over that to see if I made a mistake

I did 2L(5) + 180(5)/L + 280(15)/L for cost... but that should be correct either way....

make that 280 up there

If those are both 280 instead of 180 it should be ok.

It just means that your L is my W.

it is...they are :)

10L +900/L + 4200/L = cost

Ok then you would have
\[Cost' = 10 -900/L^2 - 4200/L^2\]

right... you derived them seperately which is fine :)

10L^2 - 5100 = 0
L^2 - 510 = 0

L=sqrt(510)....
is it right? the same as yours?

you get L = sqrt(140)

Yeah.

But my L is your W remember.

hmmm....... maybe thats right, havent checked that out yet :)

11.83 = you
12.40 = me.....

Hrm. Lemme check that cost again.

280*5 = 1400 ... not 900

Ah. That'll do it.

sqrt(560).... might be better :)

Yep... thats it.... I just forgot how to multiply integers LOL

Yep, much better.

Thats why I always save the plugging the numbers part for last.

Or as late as I can without making it look horrible.

yeah.... itda helped if I started out with the 280 and worked it, but..... you know :)