anonymous
  • anonymous
take derivative:
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[(x+1\1-x )^{2}\]
anonymous
  • anonymous
will i use quotient rule first then chain rule
anonymous
  • anonymous
Chain rule then quotient rule

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anonymous
  • anonymous
move the 2 down first then quotient rule the inside.
anonymous
  • anonymous
will i move 2 down multiply(inside) then multiply by quotient rule did that make sense?
anonymous
  • anonymous
yes. So it ends up being 2(inside)(quotient-ruled-fraction)
anonymous
  • anonymous
I am working on this and I know it is not correct, but too difficult to type the problem out. 2(x+1/1-x) (2/(1-x)^2) ????????
anonymous
  • anonymous
Quotient rule: for simplification: T=top numerator, B=bottom denominator. (T/B)'= ((T')*B-(B')*T)/(B^2)
anonymous
  • anonymous
2(x+1/1-x) is correct so far... just follow the quotient rule for the inside, multiply and you're done.
anonymous
  • anonymous
i did that and got [this is after the 2(x+1/1-x) ]] (1-x)(1)-(x+1)(-1)/(1-x)^2
anonymous
  • anonymous
then after that i get 2(x+1/1-x) (1-x+x+1/(1-x)^2 is that ok so far
anonymous
  • anonymous
Yeah that's correct.
anonymous
  • anonymous
ok then i get 2(x+1/1-x) [2/(1-x)^2] what about that
anonymous
  • anonymous
Yeah. that's good too. Then you can combine fractions again.
anonymous
  • anonymous
ok then I get 2(2x+2/x^2-2x+1
anonymous
  • anonymous
No. Im not sure what you did there.
anonymous
  • anonymous
2(x+1/1-x) [2/(1-x)^2] top: 2* (x+1)* 2 bottom: (1-x) * (1-x)^2
anonymous
  • anonymous
so should i have 4x+4 on top
anonymous
  • anonymous
Yup.
anonymous
  • anonymous
then bottom should be x^2-2x+1
anonymous
  • anonymous
never mind one 1-x is ^2
anonymous
  • anonymous
yeah. all the bottom components are the same, so just make it (1-x)^3
anonymous
  • anonymous
thanks for your help, i knew more than i thought. i just needed a little guidance

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