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will i use quotient rule first then chain rule
Chain rule then quotient rule
move the 2 down first then quotient rule the inside.
will i move 2 down multiply(inside) then multiply by quotient rule did that make sense?
yes. So it ends up being 2(inside)(quotient-ruled-fraction)
I am working on this and I know it is not correct, but too difficult to type the problem out. 2(x+1/1-x) (2/(1-x)^2) ????????
Quotient rule: for simplification: T=top numerator, B=bottom denominator. (T/B)'= ((T')*B-(B')*T)/(B^2)
2(x+1/1-x) is correct so far... just follow the quotient rule for the inside, multiply and you're done.
i did that and got [this is after the 2(x+1/1-x) ]] (1-x)(1)-(x+1)(-1)/(1-x)^2
then after that i get 2(x+1/1-x) (1-x+x+1/(1-x)^2 is that ok so far
Yeah that's correct.
ok then i get 2(x+1/1-x) [2/(1-x)^2] what about that
Yeah. that's good too. Then you can combine fractions again.
ok then I get 2(2x+2/x^2-2x+1
No. Im not sure what you did there.
2(x+1/1-x) [2/(1-x)^2] top: 2* (x+1)* 2 bottom: (1-x) * (1-x)^2
so should i have 4x+4 on top
then bottom should be x^2-2x+1
never mind one 1-x is ^2
yeah. all the bottom components are the same, so just make it (1-x)^3
thanks for your help, i knew more than i thought. i just needed a little guidance