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anonymous
 5 years ago
how do you solve this equation (20r)^1/2=r
anonymous
 5 years ago
how do you solve this equation (20r)^1/2=r

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0naynay, you need to square both sides so you can get access to the r under the square root. So\[20r=r^2 \rightarrow r^2+r20=0\]which is quadratic. This can now be factored as\[(r+5)(r4)=0\]so \[r=5\]or\[r=4\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how do you solve this (6b)^1/2=(82b)^1/2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You have to remove the square roots. You do this by squaring. Whatever you do to one side, you must do to the other, so,\[\sqrt{6b}=\sqrt{82b} \rightarrow 6b=82b \rightarrow 8b=8 \rightarrow b=1\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh ok i see what you did

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok this one i really dont get 3=(373n)^1/2n

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Have you become a fan yet?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You're always looking to isolate your variable. Here I would add n to both sides and then square both sides, so\[n3=\sqrt{373n} \rightarrow (n3)^2=373n\]Then expand the left hand side\[n^26n+9=373n \rightarrow n^23n28=0\]which you can then solve by factoring.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0where did you get 37 from

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You gave it to me in your question: 3=(373n)^1/2n

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh ok im sorry didnt look twice =)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you a lot with helping me because im really not all that good in math

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You're welcome. All you need is practice.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Things will start to click.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah i have a friend of mine comin to help me twice a week so hopefully it work =)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm sure it will. Good luck, and you can use this site too for help.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah i like this site a lot it does help

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you help me with this (34x)^1/2(22x)^1/2=1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{34x}\sqrt{22x}=1\]Okay, for ones like this, it's best to move one of the square roots to the other side and then square both sides:\[\sqrt{34x}=1+\sqrt{22x}\]square both sides:\[34x=\left( 1+\sqrt{22x} \right)^2\]Now the hard part is to expand the righthand side\[\left( 1+\sqrt{22x} \right)^2=1+2\sqrt{22x}+\left( \sqrt{22x} \right)^2\]\[=1+2\sqrt{22x}+(22x)\]\[=12x+\sqrt{22x}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so this girl helped me and we got it right =)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay, so now looking at this, we have the problem of the square root again. This is because of the expansion we had to do earlier BUT we can get rid of it using the same technique as before  move everything that has nothing to do with the square root to the other side, and then square both sides.\[34x=12x\sqrt{22x}\]becomes\[22x=\sqrt{22x}\]which is the same as\[\sqrt{22x}=2+2x \rightarrow 22x=(2+2x)^2\]\[22x=4+8x+4x^2 \rightarrow 4x^2+10x+6=0\]i.e.\[2x^2+5x+3=0 \rightarrow (x+2)(x+3)=0 \rightarrow x=2,3\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, I just thought I'd finish it.
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