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since 1^2=1, 2^2=4, 3^2=9, 4^2=16,...,n^2
so what would the nth term be?
oh n^2 ok
What about the sequence 3, 11, 31, 69, 131
myininaya are you there?
I'm trying to see the pattern
The first differences would be 3, 20, 38, 62. The second differences would be 12, 18, 23 and 30. The third difference would be 6 for all of them
Oh I meant 24 not 23
Are you still there?
That's funny. Both answers are correct.
My answer was that the nth term was the sum of the first n odd natural numbers.
So the first number is
1, the second is 1+3=4, the third is 1+3+5=9, the fourth is 1+3+5+7 = 16
polpak did you get my second question?
Yeah, looking at it, but these things are kinda lame cause there's a lot of different ways you can approach it.