## anonymous 5 years ago how do you solve (-3-4x)^1/2-(-2-2x)^1/2=1

1. anonymous

alright, if I'm not wrong , you'll have to multiply the left side with $\sqrt{-3-4x} +\sqrt{-2-2x}$ up and down , then you'll get : $(-3x-4x) -(-2-2x) = 1$ simply subtract and solve for x and you'll get : $-3-4x +2 +2x -1 = 0$ -2x -1 -1 = 0 -2x = 2 x = -1 Correct me if I'm wrong ^_^

2. anonymous

oh thank you so much thank you =) i was really having a hard time with this

3. anonymous

and i will

4. anonymous

yeah i think your right

5. anonymous

you're welcome ^_^ good luck!