5x(x^2+7x-4)

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do you know what distributing is?
no
then lets do a simple example: we know that 3(8) = 24 right?

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Other answers:

yeaa
then: 3(6+2) should equal 24 also right?
yes
good: what we are going to do then is "distribute" the 3 thru the (6+2) like this: 3(6) + 3(2) = 24 18 + 6 = 24 24 = 24. did you see what I did?
yes i understand that but i dont understand it when it has exponets and letters
fair enough..... those are simple rules as well..but lets use your problem: 5x(x^2+7x-4) 5x(x^2) + 5x(7x) + 5x(-4) 5xxx + 35xx + -20x 5x^3 + 35x^2 - 20x did you see what happened? with the x's?
x^2 means you have 2 little x's x^2 = xx x^5 = xxxxx x^9 = xxxxxxxxx
when we multiply "letters" we just tack on another one: xx time xxx = xxxxx x^2 times x^3 = x^5
okk
easy as ....pi :)
can you help me with a dividing one?
i can try...
5x3 +10x2 +20x/5x
is that 5x on the end the denominator for ALL of them? or just for the last one?
for all
ok.... for this we need to remember that anything over itself can be "canceled" out..... actually it turns to 1. lets do the first term: 5xxx ----- anything that is the same can be canceled 5x take off a 5x from top and bottom to get: [5x]xx xx = x^2 does that makes sense? ------ = [5x]
yes
2nd term: 10xx ----- what can we do to this one? 5x
is it gunna be 2x?
very good :)
and the last one? 20x ------ 5x
4x?
4 is right, but we can cancel out an x from top and an x from bottom, so the answer becomes just: 4 do you see that?
yea i wasnt sure but i see it now
good job :) with practice youlll be better than me :)
haha thank you

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