anonymous
  • anonymous
HELP ME SIMPLiFY:
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
1.\[15a ^{-4}b ^{-6} \over 3a ^{7}b ^{-10}\]
anonymous
  • anonymous
steps please :)
anonymous
  • anonymous
alright, let's get the negative powers positive by switching their places and we'll get :\[= (15b^{10})/(3a^7a^4b^6)\] so now we know that : \[= (3)(5)b^{10}/3a^{11}b^6\] let's cancel out the commons and simplify ^_^: \[= 5b^4/a^{11}\] get the idea now? :)

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anonymous
  • anonymous
we subtract the powers :)
anonymous
  • anonymous
i am confused on the top part...you but 3a^7 a^4 .... how did you get two a's
anonymous
  • anonymous
lol, okay, we want to get the powers (+) instead of (-) so in order to do that, if we have a negative powe in the top we get it down to get it positive and vice versa ^_^
anonymous
  • anonymous
power*
anonymous
  • anonymous
so I got a^-4 down to make it a^4 :)
anonymous
  • anonymous
to make your life easier ^_^
anonymous
  • anonymous
ok so you brought that down i get that
anonymous
  • anonymous
how did you get b ^10
anonymous
  • anonymous
yep, same thing goes with b too ^_^
anonymous
  • anonymous
oh since it was - you brought it up to be pos.
anonymous
  • anonymous
you want b^-10 positive, so you get it up to make it b^10 :) switch the places
anonymous
  • anonymous
exactly ^_^
anonymous
  • anonymous
ok
anonymous
  • anonymous
then we simplify and subtract, b^10 - b^6 = b^4 and the one with the greatest power takes the lead, which means the answer stays up :)
anonymous
  • anonymous
got the point? ^_^
anonymous
  • anonymous
yes thanks so much, i have two other problems i posted if you get a chance i would love your help!
anonymous
  • anonymous
np, I'll take a look ^_^

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