## anonymous 5 years ago HELP ME SIMPLiFY:

1. anonymous

1.$15a ^{-4}b ^{-6} \over 3a ^{7}b ^{-10}$

2. anonymous

3. anonymous

alright, let's get the negative powers positive by switching their places and we'll get :$= (15b^{10})/(3a^7a^4b^6)$ so now we know that : $= (3)(5)b^{10}/3a^{11}b^6$ let's cancel out the commons and simplify ^_^: $= 5b^4/a^{11}$ get the idea now? :)

4. anonymous

we subtract the powers :)

5. anonymous

i am confused on the top part...you but 3a^7 a^4 .... how did you get two a's

6. anonymous

lol, okay, we want to get the powers (+) instead of (-) so in order to do that, if we have a negative powe in the top we get it down to get it positive and vice versa ^_^

7. anonymous

power*

8. anonymous

so I got a^-4 down to make it a^4 :)

9. anonymous

to make your life easier ^_^

10. anonymous

ok so you brought that down i get that

11. anonymous

how did you get b ^10

12. anonymous

yep, same thing goes with b too ^_^

13. anonymous

oh since it was - you brought it up to be pos.

14. anonymous

you want b^-10 positive, so you get it up to make it b^10 :) switch the places

15. anonymous

exactly ^_^

16. anonymous

ok

17. anonymous

then we simplify and subtract, b^10 - b^6 = b^4 and the one with the greatest power takes the lead, which means the answer stays up :)

18. anonymous

got the point? ^_^

19. anonymous

yes thanks so much, i have two other problems i posted if you get a chance i would love your help!

20. anonymous

np, I'll take a look ^_^