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anonymous

  • 5 years ago

HELP ME SIMPLiFY:

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  1. anonymous
    • 5 years ago
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    1.\[15a ^{-4}b ^{-6} \over 3a ^{7}b ^{-10}\]

  2. anonymous
    • 5 years ago
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    steps please :)

  3. anonymous
    • 5 years ago
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    alright, let's get the negative powers positive by switching their places and we'll get :\[= (15b^{10})/(3a^7a^4b^6)\] so now we know that : \[= (3)(5)b^{10}/3a^{11}b^6\] let's cancel out the commons and simplify ^_^: \[= 5b^4/a^{11}\] get the idea now? :)

  4. anonymous
    • 5 years ago
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    we subtract the powers :)

  5. anonymous
    • 5 years ago
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    i am confused on the top part...you but 3a^7 a^4 .... how did you get two a's

  6. anonymous
    • 5 years ago
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    lol, okay, we want to get the powers (+) instead of (-) so in order to do that, if we have a negative powe in the top we get it down to get it positive and vice versa ^_^

  7. anonymous
    • 5 years ago
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    power*

  8. anonymous
    • 5 years ago
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    so I got a^-4 down to make it a^4 :)

  9. anonymous
    • 5 years ago
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    to make your life easier ^_^

  10. anonymous
    • 5 years ago
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    ok so you brought that down i get that

  11. anonymous
    • 5 years ago
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    how did you get b ^10

  12. anonymous
    • 5 years ago
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    yep, same thing goes with b too ^_^

  13. anonymous
    • 5 years ago
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    oh since it was - you brought it up to be pos.

  14. anonymous
    • 5 years ago
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    you want b^-10 positive, so you get it up to make it b^10 :) switch the places

  15. anonymous
    • 5 years ago
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    exactly ^_^

  16. anonymous
    • 5 years ago
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    ok

  17. anonymous
    • 5 years ago
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    then we simplify and subtract, b^10 - b^6 = b^4 and the one with the greatest power takes the lead, which means the answer stays up :)

  18. anonymous
    • 5 years ago
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    got the point? ^_^

  19. anonymous
    • 5 years ago
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    yes thanks so much, i have two other problems i posted if you get a chance i would love your help!

  20. anonymous
    • 5 years ago
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    np, I'll take a look ^_^

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