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anonymous
 5 years ago
Identify the correct categories for the solution to the following equation.
I. Natural
II. Whole
III. Integer
IV. Rational
V. Irrational
x²=36
a.)1 and II
b.)III and IV
c.)II, III, and IV
d.)II and III
anonymous
 5 years ago
Identify the correct categories for the solution to the following equation. I. Natural II. Whole III. Integer IV. Rational V. Irrational x²=36 a.)1 and II b.)III and IV c.)II, III, and IV d.)II and III

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The answer is integer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i'm pretty sure it's neither natural nor irrational. it's ineteger because x²=36 > x=6 or x=6 so you can eliminate choice a and c

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It can't be Natural, due to the presence of 6

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the right answer is b

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It can't be whole due to the same reason

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can call it rational, but integer is a better option

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So the answer having both rational and integer is the right one

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Whole means 0,1,2,3......................

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There is no negative in whole

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the answer is b riqht ? cuss its rationaL ?

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0You can solve that equation in any of those categories, but irrational makes no sense as there are constants (2 and 36) in the equation, that are not irrational. All the others are ok. Of course you will get sometimes more solutions and sometimes less. But the equation itself does not tell you which category you should take. And you could always define a bigger category with still more solutions. (For example you have a solution in ℝ^2: \[\begin{pmatrix}5\\\sqrt{11}\end{pmatrix}^2 =\begin{pmatrix}5\\\sqrt{11}\end{pmatrix}\cdot\begin{pmatrix}5\\\sqrt{11}\end{pmatrix} = 36\] Oh and what your the difference between whole and integer numbers? So why is the answer b and not c?

nikvist
 5 years ago
Best ResponseYou've already chosen the best response.0Answer is c because \[Z\in Q\]

nikvist
 5 years ago
Best ResponseYou've already chosen the best response.0Correction \[Z\subset Q\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes i think you're right i googled about whole number and it's almost the same as integer so the right answer is c

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Could you provide me some help on this Well, here is my next question http://openstudy.com/updates/4d9abb520b248b0b471ce9e2?source=email#/updates/4d9ac0cf0b248b0bdc1fe9e2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is this the question?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This not the question

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There is some problem with the site

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am providing the link.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://openstudy.com/groups/mathematics#/updates/4d9ac0cf0b248b0bdc1fe9e2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://openstudy.com/groups/mathematics#/updates/4d9ac0cf0b248b0bdc1fe9e2
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