Identify the correct categories for the solution to the following equation. I. Natural II. Whole III. Integer IV. Rational V. Irrational x²=36 a.)1 and II b.)III and IV c.)II, III, and IV d.)II and III

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Identify the correct categories for the solution to the following equation. I. Natural II. Whole III. Integer IV. Rational V. Irrational x²=36 a.)1 and II b.)III and IV c.)II, III, and IV d.)II and III

Mathematics
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The answer is integer
X=+-6
i'm pretty sure it's neither natural nor irrational. it's ineteger because x²=36 -> x=-6 or x=6 so you can eliminate choice a and c

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It can't be Natural, due to the presence of -6
so the right answer is b
It can't be whole due to the same reason
You can call it rational, but integer is a better option
So the answer having both rational and integer is the right one
b or c ? hmm . . .
is it whoLe ?
No not whole
Whole means 0,1,2,3......................
There is no negative in whole
the answer is b riqht ? cuss its rationaL ?
yes
You can solve that equation in any of those categories, but irrational makes no sense as there are constants (2 and 36) in the equation, that are not irrational. All the others are ok. Of course you will get sometimes more solutions and sometimes less. But the equation itself does not tell you which category you should take. And you could always define a bigger category with still more solutions. (For example you have a solution in ℝ^2: \[\begin{pmatrix}5\\\sqrt{11}\end{pmatrix}^2 =\begin{pmatrix}5\\\sqrt{11}\end{pmatrix}\cdot\begin{pmatrix}5\\\sqrt{11}\end{pmatrix} = 36\] Oh and what your the difference between whole and integer numbers? So why is the answer b and not c?
Answer is c because \[Z\in Q\]
Correction \[Z\subset Q\]
yes i think you're right i googled about whole number and it's almost the same as integer so the right answer is c
okay thanks ! :D
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