f(x)=3x^2-12x+5, find the absolute max and min value of f(x) on the interval [0,1]. From f'(x), i found x=2. Is this valid to use it on f(x) to check the min/max value? Or is it out of the interval?

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f(x)=3x^2-12x+5, find the absolute max and min value of f(x) on the interval [0,1]. From f'(x), i found x=2. Is this valid to use it on f(x) to check the min/max value? Or is it out of the interval?

Mathematics
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yes, you can use it on f(x) to get the max/min value
but the function wil only have a minimum value, the max value is infinity
this interval [0,1]. is this means x,y format? or x=0 and x=1

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oh, i didnt see there's an interval. you can't use x=2 then
so i found that f(0) is the maximum, and f(1) is the minimum. Is this correct?
i think so f(0) = 5 and f(1) = abs(-4) = 4
and also out of question, the f''(x) can be used for finding local max min, yes?
i have f''(x) =6, and i need to find local min max in interval [1,infinity]
yes, from wikipedia : If then has a local maximum at . If then has a local minimum at . If , the second derivative test says nothing about the point , a possible inflection point.
if f''(x) < 0 then f(x) has a local maximum at x if f''(x) > 0 then f(x) has a local minimum at x
then for my problem is i dont have local maximum? since i have only f''(x)= 6 which is > 0
yes you dont, the function only has one minimum point
thank you, that was very helpful. :)
you're welcome

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