anonymous
  • anonymous
f(x)=3x^2-12x+5, find the absolute max and min value of f(x) on the interval [0,1]. From f'(x), i found x=2. Is this valid to use it on f(x) to check the min/max value? Or is it out of the interval?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
yes, you can use it on f(x) to get the max/min value
anonymous
  • anonymous
but the function wil only have a minimum value, the max value is infinity
anonymous
  • anonymous
this interval [0,1]. is this means x,y format? or x=0 and x=1

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anonymous
  • anonymous
oh, i didnt see there's an interval. you can't use x=2 then
anonymous
  • anonymous
so i found that f(0) is the maximum, and f(1) is the minimum. Is this correct?
anonymous
  • anonymous
i think so f(0) = 5 and f(1) = abs(-4) = 4
anonymous
  • anonymous
and also out of question, the f''(x) can be used for finding local max min, yes?
anonymous
  • anonymous
i have f''(x) =6, and i need to find local min max in interval [1,infinity]
anonymous
  • anonymous
yes, from wikipedia : If then has a local maximum at . If then has a local minimum at . If , the second derivative test says nothing about the point , a possible inflection point.
anonymous
  • anonymous
if f''(x) < 0 then f(x) has a local maximum at x if f''(x) > 0 then f(x) has a local minimum at x
anonymous
  • anonymous
then for my problem is i dont have local maximum? since i have only f''(x)= 6 which is > 0
anonymous
  • anonymous
yes you dont, the function only has one minimum point
anonymous
  • anonymous
thank you, that was very helpful. :)
anonymous
  • anonymous
you're welcome

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