anonymous
  • anonymous
find the slope of the tangent line to the curve -1x^2-2xy-3xy^3=-185 at point (-1,4)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
sorry i mean at point (-2,-4)
anonymous
  • anonymous
The derivative if this function is-2x-2y-2xy'-3y^3-3x3y^2y'
anonymous
  • anonymous
Y'=...... Make the (-2,-4)in

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anonymous
  • anonymous
oh crap i wrote the equation wrong... sorry it's actually -1x^2-4xy-2y^3=92
anonymous
  • anonymous
The derivative if this function is-2x-2y-2xy'-3y^3-3x3y^2y'=-185.so y'=. And then make (-2,-4)in.
anonymous
  • anonymous
ok so if we're taking the derivative of this equation -1x^2-4xy-2y^3=92
anonymous
  • anonymous
would it be -2x-4xy'=4y-6y^2y'=0
anonymous
  • anonymous
No, it is a implicit function.
anonymous
  • anonymous
yes it is, i took the derivative and that's what i got, idk if it's right tho
anonymous
  • anonymous
So we can make it-------- -2x-4y-4xy'-6y^2y'=92. X=-2. Y=-4 So. 4+16+8y'-96y'=92 so y'=72/-88=-9/11
anonymous
  • anonymous
Maybe I am wrong. It is too hard to write on iPad
anonymous
  • anonymous
Sorry i am wrong. I forget to make 92 into 0
anonymous
  • anonymous
yea so it would be -2x-4xy'=4y-6y^2=0
anonymous
  • anonymous
sorry typo... i meant -2x-4xy'+4y-6y^2y'=0

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