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anonymous
 5 years ago
A rectangular plot of land is to be fenced in using two kinds of fencing. Two opposite sides
will use heavyduty fencing selling for $3 a foot, while the remaining two sides will use standard
fencing selling for $2 a foot. What are the dimensions of the rectangular plot of greatest area
that can be fenced in at a cost of $6000?
anonymous
 5 years ago
A rectangular plot of land is to be fenced in using two kinds of fencing. Two opposite sides will use heavyduty fencing selling for $3 a foot, while the remaining two sides will use standard fencing selling for $2 a foot. What are the dimensions of the rectangular plot of greatest area that can be fenced in at a cost of $6000?

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radar
 5 years ago
Best ResponseYou've already chosen the best response.0Let x = length Let y = width From this we know that area A=xy.

radar
 5 years ago
Best ResponseYou've already chosen the best response.0We also know that perimeter is P=2x+2y we also know that cost would be 3(2x)+2(2y) or 6x +4y=$6,000.00. From this cost equation we solve for x in terms of y 6x=60004y x=1000(4y)/6.

radar
 5 years ago
Best ResponseYou've already chosen the best response.0We now substitute this value in the area equation A=xy. A=(10004y/6)y \[A=1000y4y ^{2}/6=1000y2y ^{2}/3\] differentiate and set to equal zero (0) \[1000(4y/3)=0 \] Solve for y and obtain y=750ft

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Then solve for x, getting x=500. the cost then becomes $3000 for the x sides (2*500*$3.000) and $3000 for the two y sides (2*750*$2.00)

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Did you follow with understanding?

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Great, have a nice day :)
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