A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 5 years ago

How do I find an equation of the line containing the centers of the following two circles? x2 +y2-4x+6y+4=0 and x2+y2+6x+4y+9=0

  • This Question is Closed
  1. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    find the coordinates for the centers of each circle and find the slope between them and plug them into the line equation :)

  2. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    (x^2-4x+n) + (y^2 +6y +m) = -4 +n +m (x^2 -4x +4) + (y^2 +6x +9) = -4 +4 +9 (x-2)^2 + (y+3)^2 = sqrt(9) = 3 center is at (x=2, y=-3) (2,-3)

  3. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    (x^2 +6x +n)+(y^2 +4y +m) = -9+n+m (x^2 +6x +9) + (y^2 +4x +4) = -9 +9 +4 (x+3)^2 + (y+2)^2 = sqrt(4) = 2 center of circle is at (x=-3, y=-2) (-3,-2)

  4. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    (2,-3) (-3,-2) m = (y1 -y2)/(x1-x2) m= -3--2/2--3 = -3+2/2+3 = -1/5 y = mx+b y = (-1/5)x + b -2=(-1/5)(-3) + b -2 = 3/5 + b -2 - 3/5 = b -13/5 = b y = (-1/5)x - 13/5 OR x + 5y = 13

  5. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    might want another look at that....

  6. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    x + 5y = -13 is better :)

  7. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.