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anonymous
 5 years ago
I really need help. I am 50 yrs old, and these math problems are killing me. If I do not pass, I do not graduate. I am looking for help with base ten/base five/ base two/ ect. type problems including binary as well. 1st problem is 79 base two.
anonymous
 5 years ago
I really need help. I am 50 yrs old, and these math problems are killing me. If I do not pass, I do not graduate. I am looking for help with base ten/base five/ base two/ ect. type problems including binary as well. 1st problem is 79 base two.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.079:2=391 39:2=191 19:2=91 9:2=41 4:2=20 2:2=10 1:2=01 \[79_{10}=1001111_2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.079 in binary (base 2) is 1001111. The base is how many numbers there are per character (ie base ten has 09 which is ten, base 2 has 01 which is two) in binary each slot means a different ammount. first 1, then 2 then 4 then 16 and so on (eash slot is *2 of the previous slot) so for your 79 example that means theres a 1, a 2, a 4, a 8, no 16, no 32, and a 64. note that 1+2+4+8+0+0+64=79

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.079 in uninary is: 1111111111111111111111111111111111111111111111111111111111111111111111111111111

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for base five you would have 1,2,3,4 then 10 would be 5. 11 would be 6, 12 would be 7 and so on

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0google this stuff up, and there you will find some articles how to do it also, I would recomend you to ask someone from the place you are about to graduate at to help you out. Just dont be afraid to ask.
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