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anonymous

  • 5 years ago

The pressure P (in pounds per square foot), in a pipe varies over time. Ten times an hour, the pressure oscillates from a low of 40 to a high of 280 and then back to a low of 40. The pressure at time t = 0 is 40. Let the function P = f(t) denote the pressure in pipe at time t minutes. Find the formula for the function P=f(t)

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  1. amistre64
    • 5 years ago
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    can we use trig? it sounds like an upside down cosine function thats been shifted up

  2. amistre64
    • 5 years ago
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    -120cos(x) +160

  3. amistre64
    • 5 years ago
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    the oscillation is a clue to the "period" of the function

  4. amistre64
    • 5 years ago
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    60/10 = every 6 minutes

  5. amistre64
    • 5 years ago
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    if 6 minutes is the period, but 1 minutes is the normal period then we got: P(t) = -120cos(t/6) + 160 maybe?

  6. amistre64
    • 5 years ago
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    at t=3 we should have 280 -120(cos(1/2)) +160...its alittle off, but something to work with. just gotta determine the right value for the period.

  7. amistre64
    • 5 years ago
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    -120(cos(pi/3)(t)) + 160....getting warmer?

  8. amistre64
    • 5 years ago
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    im sure thats it: P(t) = -120cos[(pi/3)*t] +160

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