The pressure P (in pounds per square foot), in a pipe varies over time. Ten times an hour, the pressure oscillates from a low of 40 to a high of 280 and then back to a low of 40. The pressure at time t = 0 is 40. Let the function P = f(t) denote the pressure in pipe at time t minutes. Find the formula for the function P=f(t)

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The pressure P (in pounds per square foot), in a pipe varies over time. Ten times an hour, the pressure oscillates from a low of 40 to a high of 280 and then back to a low of 40. The pressure at time t = 0 is 40. Let the function P = f(t) denote the pressure in pipe at time t minutes. Find the formula for the function P=f(t)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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can we use trig? it sounds like an upside down cosine function thats been shifted up
-120cos(x) +160
the oscillation is a clue to the "period" of the function

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Other answers:

60/10 = every 6 minutes
if 6 minutes is the period, but 1 minutes is the normal period then we got: P(t) = -120cos(t/6) + 160 maybe?
at t=3 we should have 280 -120(cos(1/2)) +160...its alittle off, but something to work with. just gotta determine the right value for the period.
-120(cos(pi/3)(t)) + 160....getting warmer?
im sure thats it: P(t) = -120cos[(pi/3)*t] +160

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