anonymous
  • anonymous
the radius of a circle is decreasing at a constant rate of .1 centimeter per second. in terms of circumference C, what is the rate of change of the area of the circle, in square centimeters per second?
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
yup. then mukltiply by whatever coefficents there are for your 4 numbers
anonymous
  • anonymous
A = pi*r^2; dA/dt = 2*pi*r*dr/dt. We know dr/dt = 0.1cm/sec. We need to know the 'r' at which we want to determine the change in area (dA/dt) and stick that into the equation: dA/dt = 2*pi*r*dr/dt
anonymous
  • anonymous
wait, why do you multiply dr/dt

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anonymous
  • anonymous
seocnd statement after Area formula
anonymous
  • anonymous
This is a related rate problem. The dA/dt is related to the dr/dt, which is a given.
anonymous
  • anonymous
Yes, you want dA/dt, which equals 2*pi*r*dr/dt
anonymous
  • anonymous
so.. the anser is -.1(2pirR)
anonymous
  • anonymous
WAIT NO

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