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anonymous

  • 5 years ago

3(y+7)/7y - (4y - 7)/6 = (7y+10)/3y - 2(7y-1)/21

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  1. anonymous
    • 5 years ago
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    solve for y

  2. anonymous
    • 5 years ago
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    (3y+21/7y)-(4y-7/6)=(7y+10/3y)-(14y-2/21) => (3y+21/7y)-(7y+10/3y)=-((14y-2/21)+(4y-7/6)) am working on the rest of the computation

  3. anonymous
    • 5 years ago
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    we will get i think -1596y²-567y+294=0 you need to do delta to find the solutions am not sure about the computation though

  4. anonymous
    • 5 years ago
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    ok so you should be able to simpliify it down to 42y^2 - 42y - 35 = 0 so factoring out a 7 would give you 6y^2 - 6y + 5 = 0 if you have learned imaginary roots: 0.5 +- i*(sqrt(21)/6)

  5. anonymous
    • 5 years ago
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    Move the right side of the equation over to the left side leaving zero on the right side and after simplifing the left side you will have the following equation: \[\frac{1}{42} \left(45-14 y-80 y^2\right)==0 \] Solve \[\left(45-14 y-80 y^2\right)==0 \]

  6. anonymous
    • 5 years ago
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    I haven't learned about imaginary roots yet. :/ I'm just learning algebraic fractions...so I'm realy confused

  7. anonymous
    • 5 years ago
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    \[y=\frac{1}{80} \left(-7\pm\sqrt{3649}\right)\]

  8. anonymous
    • 5 years ago
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    now im rly lost....

  9. anonymous
    • 5 years ago
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    After moving the right side to the left side, the left side should look like the following: \[\frac{1}{6}(7-4y)+\frac{3}{7}y(7+y)-\left(-\frac{2}{21}(-1+7y)+\frac{1}{3}y(10+7y)\right)=0\] Get rid of the fractions by multipling each fraction in front of it's term by 42, the smallest number divisible by all of the fraction denominators. Do the multiplications and collect like powers of x.

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spraguer (Moderator)
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