## anonymous 5 years ago ok so i need help finding the perimeter, the hight,the surface aria, and the slant hight of a square pyramid..who can help

1. anonymous

Pythagoras probably could have helped :(

2. anonymous

what

3. anonymous
4. anonymous

well i got that...i just have a limited about of numbers that help me at all

5. anonymous

i have a volume that =340 and values of x1-12 that equal the base lengths

6. anonymous

Is it a regular square based pyramid (i.e. the 4 triangles are equilateral)? If so, then that is probably enough. If not, you're f*cked

7. anonymous

umm...thanks

8. anonymous

I was trying to help. No need to get all dorky on me.

9. anonymous

lol...i am a dork to begin with...so im sorry but you are going to have to retard this out for me

10. anonymous

Have fun.

11. anonymous

not helping..im having issues trying to figure out what goes in the calculator

12. anonymous

What is x1? just a random number?

13. anonymous

ok so i got the perimeter which is $p=x \times 4$

14. anonymous

now i need to get the side length which is $a^2+b^2=c^2 so what is a b and c$

15. anonymous

OK I will try and do this quickly - what EXACTLY do you know?

16. anonymous

i know the volume is 340 inches cubed..and that 1 is the side length

17. anonymous

Do you mean 1 is the length of the 4 edges of the base? Or the length of the slants?

18. anonymous

oops yes that is what i ment

19. anonymous

Well if that is the case, the volume = 340 = (1/3) * 1^2 * height , so height = 1020... which sounds retardedly big. But if that was right, the slant length ^2 = 1^2 + 1020^2 And surface area = 2 * slant length * base length + base length squared Weird question, but I have to bye. bye babe xx