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anonymous

  • 5 years ago

ok so i need help finding the perimeter, the hight,the surface aria, and the slant hight of a square pyramid..who can help

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  1. anonymous
    • 5 years ago
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    Pythagoras probably could have helped :(

  2. anonymous
    • 5 years ago
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    what

  3. anonymous
    • 5 years ago
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    http://en.wikipedia.org/wiki/Pythagorean_theorem

  4. anonymous
    • 5 years ago
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    well i got that...i just have a limited about of numbers that help me at all

  5. anonymous
    • 5 years ago
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    i have a volume that =340 and values of x1-12 that equal the base lengths

  6. anonymous
    • 5 years ago
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    Is it a regular square based pyramid (i.e. the 4 triangles are equilateral)? If so, then that is probably enough. If not, you're f*cked

  7. anonymous
    • 5 years ago
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    umm...thanks

  8. anonymous
    • 5 years ago
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    I was trying to help. No need to get all dorky on me.

  9. anonymous
    • 5 years ago
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    lol...i am a dork to begin with...so im sorry but you are going to have to retard this out for me

  10. anonymous
    • 5 years ago
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    Have fun.

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  11. anonymous
    • 5 years ago
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    not helping..im having issues trying to figure out what goes in the calculator

  12. anonymous
    • 5 years ago
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    What is x1? just a random number?

  13. anonymous
    • 5 years ago
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    ok so i got the perimeter which is \[p=x \times 4 \]

  14. anonymous
    • 5 years ago
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    now i need to get the side length which is \[a^2+b^2=c^2 so what is a b and c\]

  15. anonymous
    • 5 years ago
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    OK I will try and do this quickly - what EXACTLY do you know?

  16. anonymous
    • 5 years ago
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    i know the volume is 340 inches cubed..and that 1 is the side length

  17. anonymous
    • 5 years ago
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    Do you mean 1 is the length of the 4 edges of the base? Or the length of the slants?

  18. anonymous
    • 5 years ago
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    oops yes that is what i ment

  19. anonymous
    • 5 years ago
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    Well if that is the case, the volume = 340 = (1/3) * 1^2 * height , so height = 1020... which sounds retardedly big. But if that was right, the slant length ^2 = 1^2 + 1020^2 And surface area = 2 * slant length * base length + base length squared Weird question, but I have to bye. bye babe xx

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