ok so i need help finding the perimeter, the hight,the surface aria, and the slant hight of a square pyramid..who can help

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ok so i need help finding the perimeter, the hight,the surface aria, and the slant hight of a square pyramid..who can help

Mathematics
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Pythagoras probably could have helped :(
what
http://en.wikipedia.org/wiki/Pythagorean_theorem

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well i got that...i just have a limited about of numbers that help me at all
i have a volume that =340 and values of x1-12 that equal the base lengths
Is it a regular square based pyramid (i.e. the 4 triangles are equilateral)? If so, then that is probably enough. If not, you're f*cked
umm...thanks
I was trying to help. No need to get all dorky on me.
lol...i am a dork to begin with...so im sorry but you are going to have to retard this out for me
Have fun.
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not helping..im having issues trying to figure out what goes in the calculator
What is x1? just a random number?
ok so i got the perimeter which is \[p=x \times 4 \]
now i need to get the side length which is \[a^2+b^2=c^2 so what is a b and c\]
OK I will try and do this quickly - what EXACTLY do you know?
i know the volume is 340 inches cubed..and that 1 is the side length
Do you mean 1 is the length of the 4 edges of the base? Or the length of the slants?
oops yes that is what i ment
Well if that is the case, the volume = 340 = (1/3) * 1^2 * height , so height = 1020... which sounds retardedly big. But if that was right, the slant length ^2 = 1^2 + 1020^2 And surface area = 2 * slant length * base length + base length squared Weird question, but I have to bye. bye babe xx

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