how do i factor: 14x^2-47x+7=0

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

how do i factor: 14x^2-47x+7=0

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

You don't.
oh.. ok well my original problem i needed to solve was -42x^2+141x=-21 and i thought i was on the right track... maybe not?
find delta and factor using the solutions

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

what is delta?
The only thing that will make 14x^2 is (7x )*(2x ). Now, the only factors that give the 7 is 7 and 1. With this knowledge you get (7x-1)*(2x-7)
Wrong; is it possible that taking out 3 was all you were meant to do? Because it can;t go any further.
hmm.. maybe but the example i followed came up with two terms which then i put to the zero factor property... but maybe this is as far as this one goes.
what about the p and q thing?
I put it through the answer check and it said that 14x^2-47x+7 was wrong
it said the methods to solving were either the quadratic formula or by completing the square.
\[\sqrt{47^2-4 \times 7 \times 14} \notin \mathbb{Z^+}\] therefore it won't factorise Completing the square doesn't look too friendly on this one; just go with the formula
\[x = \frac{47 \pm \sqrt{1817}}{28}\] ...dunoo how that will go in your 'answer check'
haha yeah.. probably not that well.. but thanks for the help @INewton
just an update... apparently 14x^2-47x+7=) factors into (7x+1)(2x-7)... which in turn would make the real number solutions: -1/7 and 7/2

Not the answer you are looking for?

Search for more explanations.

Ask your own question