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anonymous
 5 years ago
How would i solve this?
f(x) = x^3+ax^2 + bx +c
a. over what interval f concave up? concave down?
b. show that f must have exactly one flection point.
c. given the (0,2) is the inflection point of f, compute a and c and then show that f has no critical point
anonymous
 5 years ago
How would i solve this? f(x) = x^3+ax^2 + bx +c a. over what interval f concave up? concave down? b. show that f must have exactly one flection point. c. given the (0,2) is the inflection point of f, compute a and c and then show that f has no critical point

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is concave up when the second derivative is positive and concave down when the second derivative is negative inflection points are where the second derivative crosses the xaxis so since the second derivative is always increasing it only does this once use the fact that the second derivative is 0 at inflection points to solve for a and then plug in x = 0 and y = 2 into the original equation to solve for c
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