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  • 5 years ago

How would i solve this? f(x) = x^3+ax^2 + bx +c a. over what interval f concave up? concave down? b. show that f must have exactly one flection point. c. given the (0,-2) is the inflection point of f, compute a and c and then show that f has no critical point

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  1. anonymous
    • 5 years ago
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    it is concave up when the second derivative is positive and concave down when the second derivative is negative inflection points are where the second derivative crosses the x-axis so since the second derivative is always increasing it only does this once use the fact that the second derivative is 0 at inflection points to solve for a and then plug in x = 0 and y = -2 into the original equation to solve for c

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