At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

z = 2 and
z = 1/5

I understand how to find them - I was having problems with setting the derivative to zero.

Alright; give me a minute and I'll try it out. :)

I've got f'(z)=6(z^2-2)(6z)(1-5z)^4-15(z^2-2)4(1-5z)^3
for the derivative. Look like what you got?

Sorry, accidentally stuck an x into the last factor when it was meant to be a z :P

The image cuts off at (3x^2 - 6)...is that the end? Just making sure

I get a pretty simple quadratic equation in the end..yep.

Hmm..How did you get to the quadratic equation? Sorry I don't understand

Did you get 0 = -60z^2 +12z - 20
at some point?

Did you get 0 = -60z^2 +12z - 20
at some point?

Ohhhhh...Okay. Thank you very much! I appreciate your help.

Glad to help. :)