how would you evaluate the definite integral of ((1+3x)/x^2)dx between 3 and 1?

how would you evaluate the definite integral of ((1+3x)/x^2)dx between 3 and 1?

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split the fraction into two parts with common denominators

1/x^2 + 3x/x^2
(S) x^-2 + 3x^-1 dx | [1,3]

-1/x + 3 ln(x)

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