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split the fraction into two parts with common denominators

1/x^2 + 3x/x^2
(S) x^-2 + 3x^-1 dx | [1,3]

-1/x + 3 ln(x)

-1+0 = -1
(-1/3 + ln(27)) - (-1)

3.9625 there abouts if I did it right :)

hmmmm......maybe :)

oh and you need to find the volume between 0 and pie/2

change it to exponent stuff...
(S) sin^(1/2) cos(1/2) dx

let u = sin, du = cos dx might be useful

oh ok. so intergration by parts.

dx = du/cos yeah, im still new at the integrating, but I got some skill :)

u^(1/2) cos^(1/2)
-------- gives us what?
cos

im trying change of variable first :)

really?...... but I was doing so good :)

u= sin du = cosx dx
(S) u du -> (sin^2)/2

there should be punctuation in there somehere to clear things :)

and if its bounded you dont need the +C

if its just the integral of sincos right?

yea. and the equation is uv - integral of v du, when u integrate by parts.

(S) u du -> (u^2)/2
(sin^2(x))/2 derive this and we get back to sin cos

oh. lol. right. yea i get it...oh man. aha.

you sure you dont need sqrt(sin cos) ??

and since the formula for volume is v= pie (s) f(x)^2 dx i can cancel the sqrt right?

which is found by pi (S) [f(x)]^2 dx right?

yes.... sounds good :)

what answer did you get? if you have to find it between pi/2 and 0?

lol..... yeah :) these are basic angles and stuff from trig class :)

i hate trig, i just type everything into my calc. ahha.

i made it thru 3 semesters of math without no calculator :)

last test they had odd angles that aint inthe "standard" tables.... broke my streak

ahah. well. thanks a bunch.