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anonymous
 5 years ago
how would you evaluate the definite integral of ((1+3x)/x^2)dx between 3 and 1?
anonymous
 5 years ago
how would you evaluate the definite integral of ((1+3x)/x^2)dx between 3 and 1?

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0split the fraction into two parts with common denominators

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.01/x^2 + 3x/x^2 (S) x^2 + 3x^1 dx  [1,3]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.01+0 = 1 (1/3 + ln(27))  (1)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.03.9625 there abouts if I did it right :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that is! thanks :D can you do this question? how do u find the antiderivative of sqrt (sinxcosx)? i need to find the volume of the soilid when the given graph is roated around the xaxis.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh and you need to find the volume between 0 and pie/2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0change it to exponent stuff... (S) sin^(1/2) cos(1/2) dx

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0let u = sin, du = cos dx might be useful

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh ok. so intergration by parts.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0dx = du/cos yeah, im still new at the integrating, but I got some skill :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0u^(1/2) cos^(1/2)  gives us what? cos

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0im trying change of variable first :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0actually you know what because i'm finiding the volume, i actually only need to find the antiderivative of sinxcosx

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0really?...... but I was doing so good :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0u= sin du = cosx dx (S) u du > (sin^2)/2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0there should be punctuation in there somehere to clear things :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0and if its bounded you dont need the +C

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that still doesn't make sense. if you make u=sinx, then du=cos x dx and dv=cos x and then v=sinx. we're back to where we started...?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if its just the integral of sincos right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yea. and the equation is uv  integral of v du, when u integrate by parts.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0step back to a time when you were first learning this..... they probably went thru the easier stuff first like usubstitution and change of variables

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if we can get it into the form: (S) u du then thats all we need to go, no "by parts" or nothing. (S) sin cos dx ^ ^^^ (S) u du

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(S) u du > (u^2)/2 (sin^2(x))/2 derive this and we get back to sin cos

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh. lol. right. yea i get it...oh man. aha.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you sure you dont need sqrt(sin cos) ??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0k, well the question is, find the volume of the solid obtained when the given region y=sqrt (sinxcosx)dx is roatated around the xaxis.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and since the formula for volume is v= pie (s) f(x)^2 dx i can cancel the sqrt right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0which is found by pi (S) [f(x)]^2 dx right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yes.... sounds good :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what answer did you get? if you have to find it between pi/2 and 0?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lets see: sin(x)^2  sin(0) = 0 so thats pointless 2 sin (pi/2) = 1 so I get 1/2 as the volume between 0 and 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i'm lame. my calculator was in degree mode...but i should have been able to figure it out anyways on paper.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lol..... yeah :) these are basic angles and stuff from trig class :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i hate trig, i just type everything into my calc. ahha.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i made it thru 3 semesters of math without no calculator :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0last test they had odd angles that aint inthe "standard" tables.... broke my streak

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ahah. well. thanks a bunch.
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