how would you simplify (6n/n+1)divided by (6n/n^2 +5n+4)

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how would you simplify (6n/n+1)divided by (6n/n^2 +5n+4)

Mathematics
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Alright, let's re-write it in a better form and you know that when we divide my a fraction, it's like we're multiplying the reciprocal of it so we'll get : \[(6n)/(n+1)\] multiplied by \[(n^2+5n+4)/(6n)\] so now we can cancel the 6n with the 6n and we'll be left with: \[(n^2+5n+4)/(n+1)\] now let's factor the top : \[(n+1)(n+4)/(n+1)\] and let's cancel the n+1 from top and bottom: \[n+4\] so n +4 is your final simplified answer ^_^ hope it's clear now
by a fraction* ^^"

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