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anonymous

  • 5 years ago

Can someone tell me if I did this double integral right?

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  1. anonymous
    • 5 years ago
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    Ok, the problem is evaluate the integral taking Ω: 0 less than/equal to x less than/equal to1, 0 less than/equal to y less than/equal to 4: Double integral of Ω4xy^2 dxdy First I took the integral of 4x dx from 0 to 1 and I got 2x^2, I did 2(1^2)-2(0^2) and I got 2y^2. So then I took the integral of 2y^2 from 0 to 4 and I got (1/3)(2)y^3, which is (2/3)y^3 and then I did (2/3)4^3 - (2/3)0^3 and I got (2/3)(64) which is 128/3. but my answer choices are; a) 64 b)140/3 c) 0 d) 42 e) none of the above so I think I did something wrong or the answer is none of the above. Please help!

  2. anonymous
    • 5 years ago
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    I got teh same thing you did, maybe it is a typo on the test for answer b

  3. anonymous
    • 5 years ago
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    actually none of the above

  4. anonymous
    • 5 years ago
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    oh, ok thanks, the answer none of the above then.

  5. anonymous
    • 5 years ago
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    yes

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