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you factor out the denominators and see what each one is missing...
that's it? you think you could give me an example?
I could, but itd be easier if you had a problem we could work :)
suppose these are the bottoms of two glorified fractions(rational expressions)...
(x+2)(x+1) and (x+2)(x)
what do they need to "look alike"?
good, but alittle of track. Think of the ()paranthesis as being a single number wrapped up. We cant just go adding a +1 to everything :) the left one is missing an (x) the right one is missing a (x+1) the common "numbers" are going to be: (x)(x+1)(x+2) dos that make sense?
1 1 ----- + ----- what would our common denominator of this be? (x-3) (x)
lets replace our "x" with a real value, lets use the number 5 and see if this turns this into somethng more familiar... 1 1 ----- + ----- (5-3) (5) 1 1 ----- + ----- what would our common denominator of this be? 2 5
10 is correct..now how do we make each side have a denominator of 10?
multiply 2 by 5 and 5 by2?
thats is right.... now lets use that knowledge when we turn the 5 back into an "x". 1 1 ----- + ----- what would our common denominator of this be? (x-3) (x) You do it the EXACT same way you did with the numbers, just think of the paranthesis as a single "wrapped up" number ok...
so i multiply-3 to (x)?
i hope to continue this later i have to get going thanks!!!!!
close..... your almost there :) but tell me.. is one of our numbers a (-3)? We have two "numbers": (x-3) and (x) those are the only two "numbers" we want to use. There is no (-3) in our example...... only a number that is equal to (x-3) and another number that is equal to (x).
ok :) Ciao