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anonymous
 5 years ago
What is the derivative of:
(10x3)/(2x+4)
I get: 34/(2x+4)^2
is that correct?
anonymous
 5 years ago
What is the derivative of: (10x3)/(2x+4) I get: 34/(2x+4)^2 is that correct?

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01st step I get (2x+4)(10)  (10x3)(2) / (2x+4)^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you did it right but i factored the bottom out and simplified it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok after I get the derivative I need to get the critical number(s). Will that only be a 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no its 2 b/c then the denominator = 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I see that now Thanks

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can't have a 0 in the denominator. The function is not differentiable there.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The critical points will be where the numerator is 0 and the denominator isn't.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0critical numbers the function either equals 0 or is undefined

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so I do not have any critical points then, is that correct?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Why are you looking for critical points? max/mins? or something different..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for my problem, I need to: a) find the derivative b) critical number(s) c) Intervals of increase and decrease

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{d}{dx}(10x3)(2x+4)^{1}\] \[=(10x3)\frac{d}{dx}[(2x + 4)^{1}] + (2x+4)^{1}\frac{d}{dx}[10x3]\] \[=(10x3)[2(2x+4)^{2}] + 10(2x+4)^{1}\] \[=\frac{2(10x3)}{(2x+4)^2} + \frac{10(2x+4)}{(2x+4)^2}\] \[\text{ Critical points are solutions to: }\] \[2(10x3) + 10(2x+4) = 0 \text{, } x \ne 2 \] \[\rightarrow 20x 6 20x + 40 = 0 \rightarrow \text{No solutions}\] Function has a vertical asymptote at x=2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0To find where the function is increasing/decreasing you just have to see where the derivative is > 0 or < 0 respectivly

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so will I use the 2 on a number line to test to see where it is increasing or decreasing
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