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anonymous

  • 5 years ago

Can someone help me with Surface area of pyramids and cones

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  1. anonymous
    • 5 years ago
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    Find the slant height of the regular pyramid or cone

  2. anonymous
    • 5 years ago
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    Do you know what pathagorean therom is?

  3. anonymous
    • 5 years ago
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    yeah isnt it a^2+b^2=c^2

  4. anonymous
    • 5 years ago
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    Ok so find the length of the hypotenuse of the pyramid (for the first one)

  5. anonymous
    • 5 years ago
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    so 12^2+15^2=369

  6. anonymous
    • 5 years ago
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    369=c^2 you still need to get rid of that exponent.. so you get \[3\sqrt{41}\]. Now that you have all the lengths apply the forumla for area of a triangle. Area = 1/2 * base * height

  7. anonymous
    • 5 years ago
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    Because you have 4 triangles you could change your forumla to reflect that A=4(1/2*b*h)

  8. anonymous
    • 5 years ago
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    Then don't forget the add the area of the base of the pyramid itself... width * height. Add them both up, and that's surface area.

  9. anonymous
    • 5 years ago
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    Get it?

  10. anonymous
    • 5 years ago
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    so 4(1/2*144*15)

  11. anonymous
    • 5 years ago
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    http://www.ajdesigner.com/phptriangle/isosceles_triangle_area_k.php

  12. anonymous
    • 5 years ago
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    Take the area of one of the isosceles triangles, multiply it by 4 and add it to the area of the base. Forget that 1/2 B*H I messed up

  13. anonymous
    • 5 years ago
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    know im lost

  14. anonymous
    • 5 years ago
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    Do you see the forumla for the area of an isocoles triangle I sent you?

  15. anonymous
    • 5 years ago
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    ya

  16. anonymous
    • 5 years ago
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    Ok so do you see how each side of the pyramid is an isocles triangle?

  17. anonymous
    • 5 years ago
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    ya

  18. anonymous
    • 5 years ago
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    Ok so on the forumla you know that B=12, and C and A are the same and using pythagorean theorm we know it is \[3\sqrt{41}\] So plug all those into the forumla and you will have the area of ONE side of the pyramid.

  19. anonymous
    • 5 years ago
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    82.486362509205

  20. anonymous
    • 5 years ago
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    I'm going to take your word on that... lol. Now what do you think you do?

  21. anonymous
    • 5 years ago
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    * it by 4

  22. anonymous
    • 5 years ago
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    right, and then add what?

  23. anonymous
    • 5 years ago
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    the base of 144

  24. anonymous
    • 5 years ago
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    There you go, that's the surface of a pyramid.

  25. anonymous
    • 5 years ago
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    As long as your algebra was right when putting those numbers in.

  26. anonymous
    • 5 years ago
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    so 473.96

  27. anonymous
    • 5 years ago
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    Assuming your algebra is correct, yes..

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