anonymous
  • anonymous
Can someone help me with Surface area of pyramids and cones
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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anonymous
  • anonymous
Find the slant height of the regular pyramid or cone
anonymous
  • anonymous
Do you know what pathagorean therom is?
anonymous
  • anonymous
yeah isnt it a^2+b^2=c^2

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anonymous
  • anonymous
Ok so find the length of the hypotenuse of the pyramid (for the first one)
anonymous
  • anonymous
so 12^2+15^2=369
anonymous
  • anonymous
369=c^2 you still need to get rid of that exponent.. so you get \[3\sqrt{41}\]. Now that you have all the lengths apply the forumla for area of a triangle. Area = 1/2 * base * height
anonymous
  • anonymous
Because you have 4 triangles you could change your forumla to reflect that A=4(1/2*b*h)
anonymous
  • anonymous
Then don't forget the add the area of the base of the pyramid itself... width * height. Add them both up, and that's surface area.
anonymous
  • anonymous
Get it?
anonymous
  • anonymous
so 4(1/2*144*15)
anonymous
  • anonymous
http://www.ajdesigner.com/phptriangle/isosceles_triangle_area_k.php
anonymous
  • anonymous
Take the area of one of the isosceles triangles, multiply it by 4 and add it to the area of the base. Forget that 1/2 B*H I messed up
anonymous
  • anonymous
know im lost
anonymous
  • anonymous
Do you see the forumla for the area of an isocoles triangle I sent you?
anonymous
  • anonymous
ya
anonymous
  • anonymous
Ok so do you see how each side of the pyramid is an isocles triangle?
anonymous
  • anonymous
ya
anonymous
  • anonymous
Ok so on the forumla you know that B=12, and C and A are the same and using pythagorean theorm we know it is \[3\sqrt{41}\] So plug all those into the forumla and you will have the area of ONE side of the pyramid.
anonymous
  • anonymous
82.486362509205
anonymous
  • anonymous
I'm going to take your word on that... lol. Now what do you think you do?
anonymous
  • anonymous
* it by 4
anonymous
  • anonymous
right, and then add what?
anonymous
  • anonymous
the base of 144
anonymous
  • anonymous
There you go, that's the surface of a pyramid.
anonymous
  • anonymous
As long as your algebra was right when putting those numbers in.
anonymous
  • anonymous
so 473.96
anonymous
  • anonymous
Assuming your algebra is correct, yes..

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