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anonymous
 5 years ago
Can (x+a)^2 be broken down into (xa)(x+a) ?
anonymous
 5 years ago
Can (x+a)^2 be broken down into (xa)(x+a) ?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Not unless a = 0 \[(x+a)^2 = (xa)(x+a) \rightarrow \frac{(x+a)^2}{(x+a)} = (xa) \] \[\rightarrow x+a = xa \rightarrow a = a\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a=0 is the trivial answer. For all x not equal to zero, \[(x+a)^{2}=(x+a)(x+a)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry, made a typo! I meant for all "a" not equal to zero.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, I don't know if you're a big fan of integration but I'm sure you'll be able to answer this. If I have the integral of dx / (X^4  a^4), does that break down into dx / (xa)^2(x+a)^2 . And then after that using what you've told me, does it break down further into dx / (xa)(x+a)(x+a)(x+a) ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And we're not told what a is equal to.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let \[u = x ^{2}\] then let \[b = a ^{2}\] now you have \[u^{2}a ^{2}\] factor out 1 now you have \[(a ^{2}u ^{2})\] the integral becomes \[1\int\limits du/(a ^{2}  u ^{2})\] Now you can look up the integral in a table of integrals

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0made a typo\[(b ^{2}u ^{2)}\] now the integral becomes \[1 \int\limits du / (b ^{2}  u ^{2} )\] This integral is listed in any table of integrals.
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