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anonymous

  • 5 years ago

is x^2-7x-8 factorable?

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  1. anonymous
    • 5 years ago
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    (x-8)(x+1)

  2. anonymous
    • 5 years ago
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    ohh duuhh haha

  3. anonymous
    • 5 years ago
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    it goes along with your other problem therefore (x-8)s will cancel out

  4. anonymous
    • 5 years ago
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    yeah they will also is x^2-1 factorable?

  5. anonymous
    • 5 years ago
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    its (x-1)(x+1)

  6. anonymous
    • 5 years ago
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    just expand it to x^2 + 0x + 1 its easier to factor that way

  7. anonymous
    • 5 years ago
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    i dont get that my teacher only taught us how to factor with 3 or more terms

  8. anonymous
    • 5 years ago
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    oh ok thanks

  9. anonymous
    • 5 years ago
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    no problem

  10. anonymous
    • 5 years ago
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    i've cancelled the x-8 and the x+1 in my problem and now i have ((1)/(3x))X((4x^3)/(x-1)) is that simplified?

  11. anonymous
    • 5 years ago
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    yeah that is the most simplified it can get

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