## anonymous 5 years ago a dice is thrown five times. what is the probability that we get number 6 four times??

1. anonymous

This is a binomial probability problem where your successful trial is a 6 and a fail trial is anything other than 6. So define, $p=\frac{1}{6}$and$q=\frac{5}{6}$Now the probability of obtaining a 6, four times, is$p(X=6)=^5C_4p^4q=\frac{5!}{4!(5-4)!}\left( \frac{1}{6} \right)^4\left( \frac{5}{6} \right)=5\frac{5}{6^5}=\frac{25}{1296}$

2. anonymous

thanx, now I finally get it!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!