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I do not understand ur reasoning?

do i have to multiply the probabilities?

or is it conditional probability p(A/b)

no, you should take every quadruple-combination as a single outcome.

so in total there are 6^4 results I think?

now how do i find the rest?

yes, true

is it 66/6^4

yes, thats what i did and i think there were 66?

toooooo complicated, nyway thank you

Well I get 6*6*5*4+4*6*5+6*6*5 = 1020 which makes about .787

not sure......

there you can count easily 6*5*4*3 = 360

ah, got it now, thats easier

so the answer must b 6*5*4/6^4

now yes!
thanx