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anonymous
 5 years ago
a dice is thrown four times. what is the probability that it we will get the same number at last twice???
anonymous
 5 years ago
a dice is thrown four times. what is the probability that it we will get the same number at last twice???

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nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0Count the possibilities, to get those results, without counting anything more than once. e.g. there are 6 results where all three are the same. Then divide that number by the number of all possible outcomes (which is 6^3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I do not understand ur reasoning?

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0It is an Laplace experiment. So in order to get the probability you have to divide the number of positive outcomes by the number of all outcomes.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but when you throw the dice once, you have the probability 1/6 that it is 5 for example but here the dice is thrown 4 times?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do i have to multiply the probabilities?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or is it conditional probability p(A/b)

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0no, you should take every quadruplecombination as a single outcome.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so in total there are 6^4 results I think?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now how do i find the rest?

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0There are certainly several ways to count. I would count the disjount situations 1 Pair; 2 Pairs and 1 Tripel seperately. Use binomial to see which of the dices are equal and then multiply with the possible count of numbers.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, thats what i did and i think there were 66?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0toooooo complicated, nyway thank you

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0Well I get 6*6*5*4+4*6*5+6*6*5 = 1020 which makes about .787

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0ah ok, I really made it too complicated you should look at the complementary event: "all 4 numbers are different"

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0there you can count easily 6*5*4*3 = 360

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ah, got it now, thats easier

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the answer must b 6*5*4/6^4
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