A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 5 years ago

f(x) is concave down on which interval? For f(x) = sin^2 (x/5) how about a global minimum and local maximum (which is not a global maximum) for this function? which region is it increasing?

  • This Question is Closed
  1. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Take derivative, look at 0s. Positive slope before 0 and negative after 0 means high point, and opposite means low point. So f'x=(2/5)sin(x/5) with 0s at 0,pi,2pi,3pi,4pi. Just before the first zero the slope is negative, so it is decreasing there, so 0 is a low point, and knowing sine pi will be a high point. So the concave down parts are 0,2pi,4pi... it is increasing between 0 and pi, 2pi and 3pi, 4pi and 5pi...

  2. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    derivative is sin(2x/5)/5 actually, but the method still applies

  3. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.