## anonymous 5 years ago please explain y=(11/3)cos^-1(5-2x)

1. anonymous

I assume you mean: $y=\frac{11cos^{-1}(5-2x)}{3}$ $\text{ Where }cos^{-1}\text{ is the inverse cosine function}$

2. anonymous

yes that is correct. I know \[\cos^1=-1/\sqrt{1-(5-2x^2) but don't know what to do after that

3. anonymous

yes that is correct. I know \[\cos^1=-1/\sqrt{1-(5-2x^2) but don't know what to do after that