Can someone please please help me with some more surface area of pyramids and cones???

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Can someone please please help me with some more surface area of pyramids and cones???

Mathematics
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maybe i might be able to help little bit maybe
take a screen shot of problem and upload it
for this one i need to find the slant hight, lateral area, and the surface area
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for this one i need to find the slant height
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okay hold on sec
okay on the slant height you use this formula =Lateral Area of a regular pyramid: ½ perimeter × slant height = 96 on this one
because see tha base of it is got dotted line which means you take half of 16 = 8 and * that by 12 which gives us 96
on frist one to get surface area use this formula Surface Area = Lateral Area + n × Bases.
i should of put this at the top... they are multiple choice.. for the cone the choices are a) 20 b) 10.6 C08.9 d) 14.4 e)7.1
well hummmmmmmm
yeah sorry im trying to do like 5 things at once
all good i am trying to do my math work and help others
lol
(25/4+144/4)^(1/2) = (169/4)^(1/2) = 13/2 (169/4+25/4)^(1/2) = 6.96 for side of pyramid
6.96 for side of pyramid so would this be the slant height?
?, the side going from one of the bottom corners to the top.
It's the longest side on the pyramid
for the pyramid: the slant height choices are: a)4.5cm b)5.5cm c)6.5cm d)6cm e)7.8 for the lateral area choices are: a)57.5cm^2 b)65cm^2 c)32.5cm^2 d)78cm^2 e)90cm^2 for the surface area: a)57.5cm^2 b)65cm^2 c)32.5cm^2 d)78cm^2 e)90cm^2
Ok, slant height is the height from the midpoint on the base to the top. So 6.5
for SA, .5bh*4 + b^2 b=5, h=6.5 (5)(6.5)(2)+5(5) 90cm squared
I'm guessing lateral area means without the base, so it's probably 65
All you need to know to do these problems to use the Pythagorean theorem on Right triangles to find the missing side, and area of triangles is simply .5base times height.
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