How can I find all the zeros of the the function f(x) = 9x^3 - 7x -2?

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How can I find all the zeros of the the function f(x) = 9x^3 - 7x -2?

Mathematics
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Factor it.
Or graph it. This does not look nice to factor.
Oh I see.. \((x-1)(3x+1)(3x+2)\)

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Isnt there a step in between,, like : 9x^2-6x-3=0
3x^2-2x-1=0
How did you propose graphing it without the factors, anyway, polpak?
Let me start over... shoudnt it be 9x(3)-7x-2 the zeros will be 1, -2/3, -1/3
that's what calculators are for ;p
And MDot, the first step is noting that f(1) = 0 (by inspection), so (x-1) is a factor. Then youjust go normally.
And get to the above thing, probably with (x-1)(quad) which becomes the thing above
ok so, (0)= -2 (+/- 1), (+/- 2)
and q is a factor of a(n)= 9 right?
I have no idea what you were talking about, I was just giving you the steps polpak (presumably) went through, when you asked wasn't there something in the middle. your zeros 1, -2/3, -1/3 before were right...
alright, well i guess ill keep working it

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