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anonymous

  • 5 years ago

How can I find all the zeros of the the function f(x) = 9x^3 - 7x -2?

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  1. anonymous
    • 5 years ago
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    Factor it.

  2. anonymous
    • 5 years ago
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    Or graph it. This does not look nice to factor.

  3. anonymous
    • 5 years ago
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    Oh I see.. \((x-1)(3x+1)(3x+2)\)

  4. anonymous
    • 5 years ago
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    Isnt there a step in between,, like : 9x^2-6x-3=0

  5. anonymous
    • 5 years ago
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    3x^2-2x-1=0

  6. anonymous
    • 5 years ago
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    How did you propose graphing it without the factors, anyway, polpak?

  7. anonymous
    • 5 years ago
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    Let me start over... shoudnt it be 9x(3)-7x-2 the zeros will be 1, -2/3, -1/3

  8. anonymous
    • 5 years ago
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    that's what calculators are for ;p

  9. anonymous
    • 5 years ago
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    And MDot, the first step is noting that f(1) = 0 (by inspection), so (x-1) is a factor. Then youjust go normally.

  10. anonymous
    • 5 years ago
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    And get to the above thing, probably with (x-1)(quad) which becomes the thing above

  11. anonymous
    • 5 years ago
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    ok so, (0)= -2 (+/- 1), (+/- 2)

  12. anonymous
    • 5 years ago
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    and q is a factor of a(n)= 9 right?

  13. anonymous
    • 5 years ago
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    I have no idea what you were talking about, I was just giving you the steps polpak (presumably) went through, when you asked wasn't there something in the middle. your zeros 1, -2/3, -1/3 before were right...

  14. anonymous
    • 5 years ago
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    alright, well i guess ill keep working it

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spraguer (Moderator)
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