How can I find all the zeros of the the function f(x) = 9x^3 - 7x -2?
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Not the answer you are looking for? Search for more explanations.
Isnt there a step in between,, like : 9x^2-6x-3=0
How did you propose graphing it without the factors, anyway, polpak?
Let me start over... shoudnt it be 9x(3)-7x-2
the zeros will be 1, -2/3, -1/3
that's what calculators are for ;p
And MDot, the first step is noting that f(1) = 0 (by inspection), so (x-1) is a factor. Then youjust go normally.
And get to the above thing, probably with (x-1)(quad) which becomes the thing above
ok so, (0)= -2 (+/- 1), (+/- 2)
and q is a factor of a(n)= 9 right?
I have no idea what you were talking about, I was just giving you the steps polpak (presumably) went through, when you asked wasn't there something in the middle. your zeros 1, -2/3, -1/3 before were right...