anonymous
  • anonymous
How can I find all the zeros of the the function f(x) = 9x^3 - 7x -2?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Factor it.
anonymous
  • anonymous
Or graph it. This does not look nice to factor.
anonymous
  • anonymous
Oh I see.. \((x-1)(3x+1)(3x+2)\)

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anonymous
  • anonymous
Isnt there a step in between,, like : 9x^2-6x-3=0
anonymous
  • anonymous
3x^2-2x-1=0
anonymous
  • anonymous
How did you propose graphing it without the factors, anyway, polpak?
anonymous
  • anonymous
Let me start over... shoudnt it be 9x(3)-7x-2 the zeros will be 1, -2/3, -1/3
anonymous
  • anonymous
that's what calculators are for ;p
anonymous
  • anonymous
And MDot, the first step is noting that f(1) = 0 (by inspection), so (x-1) is a factor. Then youjust go normally.
anonymous
  • anonymous
And get to the above thing, probably with (x-1)(quad) which becomes the thing above
anonymous
  • anonymous
ok so, (0)= -2 (+/- 1), (+/- 2)
anonymous
  • anonymous
and q is a factor of a(n)= 9 right?
anonymous
  • anonymous
I have no idea what you were talking about, I was just giving you the steps polpak (presumably) went through, when you asked wasn't there something in the middle. your zeros 1, -2/3, -1/3 before were right...
anonymous
  • anonymous
alright, well i guess ill keep working it

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