anonymous
  • anonymous
Find the period of the function. I REALLY need HELP! y= sec(2x+(3pi/2)) y= -4csc(3x+4) y=6tan(x-(pi/4)) y= 5sec(4pi(x)) y= tan(1/3(x+(pi/4)) y= tan(1/7x) y= 3csc(x-(pi/3)) y= 10tan((pi/2)x) y= 2cot x y= csc(5(x+(pi/5)) y= csc(1/8x) y= 7csc(x+(pi/2))
Mathematics
jamiebookeater
  • jamiebookeater
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amistre64
  • amistre64
the period of all the functions?
amistre64
  • amistre64
2pi/2 2pi/3 pi 2pi/4 3pi..... like that
amistre64
  • amistre64
sin(____ x.....) ^^ this number here modifies your normal period Whatever it is, multiply its reciprocal by the normal period of the function...

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anonymous
  • anonymous
I actually understand this thanks to you. I aced my hw :)
amistre64
  • amistre64
yay!! :)

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