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anonymous
 5 years ago
Find the period of the function. I REALLY need HELP!
y= sec(2x+(3pi/2))
y= 4csc(3x+4)
y=6tan(x(pi/4))
y= 5sec(4pi(x))
y= tan(1/3(x+(pi/4))
y= tan(1/7x)
y= 3csc(x(pi/3))
y= 10tan((pi/2)x)
y= 2cot x
y= csc(5(x+(pi/5))
y= csc(1/8x)
y= 7csc(x+(pi/2))
anonymous
 5 years ago
Find the period of the function. I REALLY need HELP! y= sec(2x+(3pi/2)) y= 4csc(3x+4) y=6tan(x(pi/4)) y= 5sec(4pi(x)) y= tan(1/3(x+(pi/4)) y= tan(1/7x) y= 3csc(x(pi/3)) y= 10tan((pi/2)x) y= 2cot x y= csc(5(x+(pi/5)) y= csc(1/8x) y= 7csc(x+(pi/2))

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the period of all the functions?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.02pi/2 2pi/3 pi 2pi/4 3pi..... like that

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0sin(____ x.....) ^^ this number here modifies your normal period Whatever it is, multiply its reciprocal by the normal period of the function...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I actually understand this thanks to you. I aced my hw :)
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