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anonymous

  • 5 years ago

LM is tangent to circle C at point M. If CN=3x-2 NL= 4x-6 amd CL= 34 what is the length of LM? I need to know the formula or someone to explain how to work this problem. I'm lost

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  1. amistre64
    • 5 years ago
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    these look like line measurements for a triangle but uts hard to tell with a picture to actually see.

  2. anonymous
    • 5 years ago
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    yes its a circle with a triangle from it. it has one side c to l and another m to l does that help

  3. amistre64
    • 5 years ago
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    if you can draw it in "paint" and post it in here, itd be more helpful. Paint is a basic program on many computers.

  4. amistre64
    • 5 years ago
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    Can you add any detail to this?

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  5. anonymous
    • 5 years ago
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    It is a triangle with one point in the middle which is C and M is on the radius and the common point of this triangle is L.

  6. amistre64
    • 5 years ago
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    C is in the middle of the line? like this?

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  7. anonymous
    • 5 years ago
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    No, the picture is of a circle hang on a minute

  8. anonymous
    • 5 years ago
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  9. anonymous
    • 5 years ago
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    its the top one

  10. amistre64
    • 5 years ago
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    a^2 + b^2 = c^2 (3x-2)^2 + LM^2 = [(3x-2)+(46-6)]^2 does this make sense to you?

  11. amistre64
    • 5 years ago
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    46-6 sposed ta be 4x-6 lol

  12. amistre64
    • 5 years ago
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    LM^2 = (7x-8)^2 - (3x-2)^2

  13. amistre64
    • 5 years ago
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    LM^2 = 49x^2 -112x +36 - 3x^2 -12x +4 LM^2 = 46x^2 -124x +40

  14. amistre64
    • 5 years ago
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    8*8 = 64 not 36.... you better do the math :)

  15. amistre64
    • 5 years ago
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    I messed up a few points there when I was expanding them.... rechack the math cause I know its wrong :)

  16. anonymous
    • 5 years ago
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    hang on let me liik yes but the formula is correct?

  17. amistre64
    • 5 years ago
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    LM^2 = 49x^2 -112x +64 -3x^2 +12x -4 the formula is correct, that I know.

  18. anonymous
    • 5 years ago
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    thank you sooo much I will be needing more help later, Im having problems finding this in my math book

  19. amistre64
    • 5 years ago
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    the pic you sent, the radius is (3x-2) so just use it as the base, then add the other 2 lengths together to get the hypotenuse, and find the missing leg...

  20. anonymous
    • 5 years ago
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    thanks

  21. anonymous
    • 5 years ago
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    im going to work this out and get back with u

  22. amistre64
    • 5 years ago
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    ok..

  23. anonymous
    • 5 years ago
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    how did u get 112x

  24. amistre64
    • 5 years ago
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    when you add the lengths together for the hypotenuse you get: (3x-2) + (4x-6) 3x -2 +4x -6 = 7x -8 (7x-8)^2 = 49x^2 - 56(2)x +64 49^2 -112x +64

  25. anonymous
    • 5 years ago
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    let me check

  26. anonymous
    • 5 years ago
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    oh I see where now

  27. anonymous
    • 5 years ago
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    I think Im still lost... I believe I am doing the x^2 wrong

  28. amistre64
    • 5 years ago
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    doing the x^2 wrong.... now your sounding as crazy as me...

  29. anonymous
    • 5 years ago
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    Im afraid to ask

  30. amistre64
    • 5 years ago
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    so what you have there is a simple triangle that has a length of 2 sides and you want to find the third side.... one side has been given to you in 2 seperate equation, and the shortest leg is simply the length of the radius which is one of the equations they gave you for the other.... plug it into the pythagoreum thrm and get your answer :)

  31. anonymous
    • 5 years ago
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    ok let me do it

  32. anonymous
    • 5 years ago
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    I believe the final answer is 16. but I will have to recheck the process again. I have to leave for now. thanks for all the help I'll be back again.

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