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anonymous
 5 years ago
Without using a calculator, find all solutions to cos(theta) = sqrt(2)/2 in the interval 0 <=theta<= 2pi. If there is more than one answer, enter your answers as a comma separated list. Your answers should be exact values (given as fractions, not decimal approximations).
anonymous
 5 years ago
Without using a calculator, find all solutions to cos(theta) = sqrt(2)/2 in the interval 0 <=theta<= 2pi. If there is more than one answer, enter your answers as a comma separated list. Your answers should be exact values (given as fractions, not decimal approximations).

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Are we allowed to assume knowledge of the 'basic' trig values  i.e. 0, pi/6, pi/4, pi/3, pi/2 ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0cos(pi/4) = sqrt(2)/2 (if we can;t assume, that can be proved with a simple triangle). cos(pix) = cos(x) => cos(pipi/4) = cos(3pi/4) = sqrt(2)/2 cos(2pix) = cos(x), so 2pi/3pi/4 = 5/4pi is also a solution

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh, you're not going to thank me? *awkward*

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha sorry I was working on my other problems...thanks
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