anonymous
  • anonymous
A regular pyramid has a triangular base with a base edge of 6 inches, a height of 10 inches, and a slant height of 10.33 inches... what is the lateral area? what is the surface area?
Mathematics
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
got piture of it
anonymous
  • anonymous
no
anonymous
  • anonymous
V[P,10,6,10.33] The volume of a pyramid is equal to (1)/(3) times the area of the length (l) times the width (w) times the height (h). V=(1)/(3)*lwh Substitute the values of the radius (l=6), the width (w=10), and the height (h=10.33) into the formula to find the volume of the pyramid. V=(1)/(3)*6*10*10.33 Cancel the common factor of 3 in the denominator of the first term (1)/(3) and the second term 6. V=(1)/(3)*6^(2)*10*10.33 Reduce the expression by removing the common factor of 3 in the denominator of the first term (1)/(3) and the second term 6. V=1*2*10*10.33 Multiply 1 by 2 to get 2. V=2*10*10.33 Multiply 2 by 10 to get 20. V=20*10.33 Multiply 20 by 10.33 to get 206.6. V=206.6

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
dont have pic so not sure does it have a,b,c answers
anonymous
  • anonymous
no
anonymous
  • anonymous
well thats the volume of pyrmind just wondering if i got numbers right
anonymous
  • anonymous
in right order
anonymous
  • anonymous
what would the lateral area be? what would the surface area be?
anonymous
  • anonymous
TO GET THE AREA WOULD BE Area = ½b × h b = base h = vertical height
anonymous
  • anonymous
30 WOULD BE THIS ONE IF 6 IS BASE WITH OR LENGHT AND 10 IS THE HEIGHT
anonymous
  • anonymous
so 30 would be the surface area? or lateral area?
anonymous
  • anonymous
30 WOULD BE SURFACE AREA
anonymous
  • anonymous
I AM WORKING ON LATERAL
anonymous
  • anonymous
lateral
anonymous
  • anonymous
The lateral area of a right pyramid can be calculated by multiplying half of the perimeter of the base by the slant height. This is summarized by the formula: LA 5 Ps.
anonymous
  • anonymous
LA=1/2 PS
anonymous
  • anonymous
1/2*30*10.33
anonymous
  • anonymous
YEA
anonymous
  • anonymous
SO MORE LESS SHOUDL BE 15
anonymous
  • anonymous
THATS HALF OF THE PERIMTERE
anonymous
  • anonymous
so lateral is 15?
anonymous
  • anonymous
WELL SAYS GOT TO TAKE THE PRYMIND AREA =30 SO 1/2 =15 * 10.33
anonymous
  • anonymous
so 77.48
anonymous
  • anonymous
double the lengths of the base edge, height, and slant height. what is the ratio of the surface area of the smaller pyramid to the larger pyramid?

Looking for something else?

Not the answer you are looking for? Search for more explanations.