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anonymous
 5 years ago
Determine the number of terms and identify the coefficient of each term of the expression.
1. 9x
2.3h8a
3.2a3sz
anonymous
 5 years ago
Determine the number of terms and identify the coefficient of each term of the expression. 1. 9x 2.3h8a 3.2a3sz

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01. There is one term and the coefficient is 9 2. There are two terms and the coefficient of h is 3, the coefficient of a is8 3. There are three terms and the coefficients are: 2 for a, 3 for s and 1 for z. Do you see what's going on?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Wow is it really that easy? Lol I really suck at math can u help me with some others try and understand?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sure. Become a fan ;p

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How do you do that i have to sign up?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There should be a blue link next to my name. It says, "Become a fan."

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you don't see it, refresh your screen. brb

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0add like terms if possible and write the result with the exponents in descending order. 4m^72m^7... I got 2m^7 is that right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Are you supposed to add 4m^7 and 2m^7?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0because if that's the case, you have\[4m^7+2m^7=6m^7\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I have no clue I typed it just as it asked lol. I thought that since ooo wait your right because 4 and 2 arnt like terms. ok so 6^7 ok so the next one is 7y^8  4y^7=?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or since there are no like terms would it be 4y^7  7y^8 since thats descending orded

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Like terms are terms that have the same letter. So 7x and 4x would be like terms because they both share 'x'. 7x and 4y are not like terms because x and y are different. When they ask you to sum like terms, they're asking you to do something like the following: 3x 7y +2x y = (3x+2x) + (7y+y) = 5x 8y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can you type out the question?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Add like terms, if possible, and write the result with the exponents in descending order. 1... 7y^8  4y^7 = .. so I figured it would be 4y^7  7y^8 seeing how I cant add the terms

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Nearly. Though, I'm glad you saw that you couldn't add the terms. The question asked for exponents in descending order, so you'd have to rearrange your answer as 7y^84y^7 which looks, to me, like what they gave you in the question anyway, by coincidence.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0o i had it backwards. ok. so here is another problem with the same question.... 3m^6+8m^54m^4+5m^62m^5 .... = 2m^6+6m^54m^4 ??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol, what happened to your m^5 term? What's 8 + 5?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.013... but since its 2m^5 wouldnt it be 8m^52m^5 to = 6m^5?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh I'm sorry, I stuffed it. It's hard deciphering. You're absolutely right. You have the hang of it :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol ok.. and i know it would make it easier if the powers actually worked on here so the numbers would be above,. So it says... Perform the indicated operation. 1. (2 + 3n^7  8n^5) + (9n^7 + 6n^5  5).. i havent worked on this one yet so let me try it then tell me if i did anything wrong

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay. I'm glad you're trying them out before asking.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yea I have to get this down. I am not the type of person to just get answers because then it takes me no where in life

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The person typin is my lil sis rejanae

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[(2+3n^78n^5) + (9n^7 + 6n^5  5)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol told you it works

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You have an excellent attitude Monae.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[3+12n^72n^5 or is it 3+12n^142n^10 /]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its suppose to be ^14 and ^10

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or \[3+12n^142n^10\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay, hang on, just need to check something.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Lol ok. and Thank You

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The 7 is actually\[7n^0\]I don't know if you've ever seen something like that. Whenever you raise a number to the power of 0, the result is 1. So when we order from highest to lowest powers, the constant goes on the end because the power of n is the lowest...0.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0These don't have to be in descending order for the exponents so the only thing i got wrong woul,d be the 3.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah, I really think you've got the hang of it. From here on, it's just practice.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yea the \[7^0\] is in chapter 5.6 lol i hvnt gotten there yet. im stil stuck on this lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So do I still have to write it descending like you did or is my answer right and I just have to replace the 3 with a 7

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If they don't ask for it, TECHNICALLY it's correct. BUT mathematicians, as a matter of course, always write the polynomial in descending order BECAUSE it makes our lives easier in the end when we're trying to calculate things. I suspect it would be easier for your teachers too.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Only problem is that my proffesor doesn't check to see if you have the right answers he only checks to see if you have something written down and that you tried the problem. I think its very idiotic to have that seeing how we won't learn if we did the homework right or not.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That's not a very good way of teaching.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But you're attitude is what will save you. You sorted this out in several minutes.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thank You soo much. I understand it now.. But trust I will be back on later for your help with those 7^0 and other problems like that.. will you be on tomorrow around the same time or friday anytime after 3?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Maybe...you can always try. You might get an email from my response here. If you click on 'view answer' or the link, it will take you back to this post. You can ask more questions here as a means of getting my attention, or you can ask others if you can't wait, by using the 'As a question...' box.
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