If a sample of Al2(SO4)3 is found to contain 5.57 · 10-3 mol of Al3+ ions how many moles of Al2(SO4)3 formula units are present? Express your answer in scientific notation.

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

If a sample of Al2(SO4)3 is found to contain 5.57 · 10-3 mol of Al3+ ions how many moles of Al2(SO4)3 formula units are present? Express your answer in scientific notation.

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

You know that one molecule of aluminium sulfate can produce two cations of Al3+, so\[2 Al^{3+} \iff Al_2(SO_4)_3\]which means one Al3+ is equivalent to 1/2 of one aluminium sulfate:\[Al^{3+} \iff \frac{1}{2}Al_2(SO_4)_3\]You have 5.55 x 10^-3 mol of Al3+, so you have\[5.57 \times 10^{-3}mol Al^{3+} \iff \frac{1}{2}5.57 \times 10^{-3}molAl_2(SO_4)_3\]that is, you have\[2.785 \times 10^{-3}molAl_2(SO_4)_3\]
To keep to the number of significant figures, the number of moles of aluminium sulfate is \[2.79 \times 10^{-3}mol\]

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Not the answer you are looking for?

Search for more explanations.

Ask your own question