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anonymous
 5 years ago
anyone know logs?
log(d)+log(2d+1)=log(7d)
anonymous
 5 years ago
anyone know logs? log(d)+log(2d+1)=log(7d)

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myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0logx+logy=log(xy) so you can use that property here

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so it becomes log(d(2d+1))=log(7d) ? what then

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So you are almost there. Multiply the d through the quantity (2d+1) and according to the property you can set that value equal to 7d and solve for d.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so log2d^2+d=log7d can just become 2d^2+d=7d?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that's correct, now solve for d.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok thanks :) I never liked logs
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