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anonymous

  • 5 years ago

anyone know logs? log(d)+log(2d+1)=log(7d)

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  1. myininaya
    • 5 years ago
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    logx+logy=log(xy) so you can use that property here

  2. anonymous
    • 5 years ago
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    so it becomes log(d(2d+1))=log(7d) ? what then

  3. anonymous
    • 5 years ago
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    So you are almost there. Multiply the d through the quantity (2d+1) and according to the property you can set that value equal to 7d and solve for d.

  4. anonymous
    • 5 years ago
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    so log2d^2+d=log7d can just become 2d^2+d=7d?

  5. anonymous
    • 5 years ago
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    that's correct, now solve for d.

  6. anonymous
    • 5 years ago
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    ok thanks :) I never liked logs

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