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anonymous

  • 5 years ago

Amy drives 45 miles to work. If she increases her average speed by 5 miles per hour, the time it takes to drive to work is decreased by 6 minutes. find her usual average speed.

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  1. anonymous
    • 5 years ago
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    45 = rt usual 45 = (r+5)t if she does increase her speed Solve both for t 45/r = t 45 /(r+5) = t 45/(r + 5) + 1/10 = 45/r multiply each term by 10r(r+5) which is your common denominator 450r + r^2 + 5r = 450r + 2250 r^2 + 5r - 2250 = 0 (r + 50)(r - 45) = 0 r = -50 or r = 45 You throw out the negative number be it cannot be her speed. Original speed was 45 mph

  2. anonymous
    • 5 years ago
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    thanks but if her time is decreased by six, woudnt the one formula be 45/(r+5)=t-6?

  3. anonymous
    • 5 years ago
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    No because it says 6 minutes and everything else is in hours... so you need to keep everything in hours.

  4. anonymous
    • 5 years ago
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    In the formula d = rt time is always in hours.

  5. anonymous
    • 5 years ago
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    ok but still then 45/(r+5)=t-1/60 ? or am I just being weird

  6. anonymous
    • 5 years ago
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    6 minutes is 6 minutes out of 60 minutes which is 1 hour One minute would be 1/60 of an hour Six minutes would be 6/60 of an hour which reduces to 1/10

  7. anonymous
    • 5 years ago
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    ....45/(r+5)=t-1/10? sorry I'm really tired :p

  8. anonymous
    • 5 years ago
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    oh haha wait nvm I see you added that in in the next step

  9. anonymous
    • 5 years ago
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    The way you have to look at it is two compare the two ways of driving. normal 45 = rt Going faster 45 = (r+5)t because we are comparing times between driving to work the two different ways we solve both sides for t. 45/r = t 45/(r + 5) = t Usually these problems say it took the same amount of time so you would put the left side of those equations equal to each other, but on this one it says that when she "sped up", it took her 6 minutes less to get to work. (which makes sense). The problem is "HOW DO WE get these equal to each other?" If "speeding" makes your time 6 minutes less than the other... then to make them equal you would add 6 to the "normal" driving. Ex. I am doing this in minutes because it is easier Normal Speeding 50m 44m 20m 14m 36m 30m So to make these "equal", you would add 6 minutes to the speeding side..

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