A peanut merchant sells two kinds of peanuts, one for 60 cents per lb and one for 50 cents per lb. How many of each should he mix to get 50lbs worth 52 cents per lb ?

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A peanut merchant sells two kinds of peanuts, one for 60 cents per lb and one for 50 cents per lb. How many of each should he mix to get 50lbs worth 52 cents per lb ?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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You are buying 50 pounds of peanuts so x = number of pounds of one kind y = number of pounds of other kind so x + y = 50 Then price wise, you pay .60 per pounds of one kind .50 per pound of other kind and you pay .52 for each of the 50 pounds so .60x + .50y = .52(50) Solve this system x + y = 50 .60x + .50y = .52(50) x + y = 50 60x + 50y = 2600 (multiplied by 100) -60x - 60y = -3000 (multiplied by -60) 60x + 50y = 2600 -10y = -400 added then up y = 40 divided by -10 substitute back in x + y = 50 x + 40 = 50 x = 10 10 pounds of the 60 cent peanuts 40 pounds of the 50 cent peanuts
thanks second one you've helped me with :)

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