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anonymous

  • 5 years ago

How do you factor x^3-6x^2+11x-6=0?

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  1. anonymous
    • 5 years ago
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    Are you trying to find the real roots?

  2. anonymous
    • 5 years ago
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    Yes, the solution is (x-1)(x-2)(x-3), I don't know how to get that

  3. anonymous
    • 5 years ago
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    possible roots will be the factors of 6(or the constant in general) which are +/-1 +/-2 +/-3 +/-6

  4. anonymous
    • 5 years ago
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    So, do you just plug those in and see what works?

  5. anonymous
    • 5 years ago
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    yea

  6. anonymous
    • 5 years ago
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    this is the only way i know ..hope it help

  7. anonymous
    • 5 years ago
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    Thats helps, thank you!

  8. anonymous
    • 5 years ago
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    dichalao's hint regarding the factors of the constant, 6 in this case, is presented at: http://www.purplemath.com/modules/rtnlroot.htm A quality plotting program can also be a great help. Refer to the attachment.

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  9. anonymous
    • 5 years ago
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    Thank you~!

  10. anonymous
    • 5 years ago
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    My pleasure.

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