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anonymous
 5 years ago
if a differential equations solution divides by x^2 and the initial condition is a point where x=0, what do you do? (problem: dy/dx=xyy or dy/dx=xy^2)
anonymous
 5 years ago
if a differential equations solution divides by x^2 and the initial condition is a point where x=0, what do you do? (problem: dy/dx=xyy or dy/dx=xy^2)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0initial condition is (0,2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can use separation by variables here and then integrate. Once you have y after integration, you can use the initial condition.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i did that, but my solution is y=(2/x^2)+2 which doesnt technically do through the initial condition

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think its a vertical asymptote which... definitely isint the point XD

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There's nothing wrong with that equation. After you put it into separable form and solve, you should get,\[\frac{x^2y}{2}+cy+1=0\]Initial condition,\[02c+1=0 \rightarrow c=\frac{1}{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can then factor out y and rearrange into the form y=y(x).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0When you separated the variable and tried to get y by itself did you include c and also multiply the y by it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ima try that, how about: y'=1+yy

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can do that problem the same way. I look at it as y' is dy/dx and then separate variables. Make sure when you do though, that the 1 goes with the y^2. So move the entire quantity.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dang, the small things get by me... that should be something like arctany=x+c? so tan(x+c)=y?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that explains why my condition is in radians

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0alright... major confusion... \[y'=(e ^{xy})\div(1+e ^{x})\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You want to solve that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Just pull out the e^(y) and it becomes separable ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0asoghaqoeraifoiafauirfhlanihusdfvnnfldanufd

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[e^ydy=\frac{e^x}{1+e^x}dx\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0differential equations are gay .

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dont tell me any more!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0tell you what? answers?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah.. dont tell me any more lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think you have the best icon...if that helps...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hahahaha it was annoyingly hard to make XD

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have a pretty good feeling that your icon is not you... though there is a significant chance that i am wrong given by the circumstances

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it could be me, since i look like that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol, how did your frigging doughnut go?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0pretty good, i have a way of doing things when i need help: use the first sentence or line of the help, fail a thousand times before i use the second, so on and so forth. so i used quite a bit, but not all of your help in the process of doing the assignment, and in the end i was flowing through it quite nicely, i compared my results to yours and they were identical, i then compared my results to the assignment and apparently the last couple steps, which i had done by hand, i could take the integral with a calculator... and then later he gave us the hand written answer, so i felt proud that i did it without a calculator... but yeah your help is insanely apreciated

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0alright im stuck at e^y=ln(1+e^x)+c initial condition is (0,1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is that y supposed to be y' (yprime)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nope, thats my solution

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0to the above equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah. You're right. Leave it like that too.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh, just plug your numbers in.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[e=\ln 2 +c \rightarrow c = e \ln 2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0any way to do that without a calc?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What's wrong with Euler's number? :p

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ah god its 1... can you check these real quick?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0not too much anymore lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I need paper...I've run out...hang on...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but all my work is shown?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I get something different for the first one. Just go to bed and I'll look at it and scan and you can look at it when you get up.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do i have to multiply the c by 2 aswell?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0my answer doesnt make sense anyways... when i find y' its all weird and quotienty

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{dy}{dx}=xy^2 \rightarrow y^{2}dy = x dx \rightarrow y^{1}=x+c\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Your boundary condition is (0,2), so

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[2^{1}=0+c \rightarrow c=\frac{1}{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So\[y^{1}+x=\frac{1}{2} \rightarrow 2+2xy=y \rightarrow y(12x)=2 \rightarrow y=\frac{2}{12x}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0waitttt the integral of xdx is (1/2)xx+c though!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh crap, I forgot the frigging x. Sorry Arman.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nah dont be sorry, i should hit the sheets tho, i'll probably have more questions tomorrow lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I still get a different answer to you.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0basic differential equations (like these) arent usually part of calc II are they?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yours is close. I'll work through them  they won't take long  and scan and you can read it in the morning.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm not sure about the American system.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0did you use (0,2) for the initial whatever?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0pellet, I wrote it wrong on my paper. I wrote (0,2). SORRY AGAIN :'(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0NOW I get what you got.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0>< nah man i hate when ppl tell me sorry

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0my calc teacher, this morning, was like "oh flutter..." *covers mouth*... *whole class starts laughing caus we hear him say pellet sometimes but never the f word so it meant he was really screwed over XD

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol, it's great when that happens. I got the same results as you for the other two. The *only* thing I would do differently is leave \[e\log 2\]as is, and not use a numerical approximation (in the last one).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats probably better in the math world, where you need to be precise

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is that prefered in college?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Absolutely. You'd only use a numerical approximation for the time you actually need to extract a number. Other than that, we leave it because we may want to do further mathematics on it and we lose information/exactness if we start approximating beforehand.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just like the AP exams lol. i think i asked you before but what are the remaining major math courses after differential eqas and linear algebra (when i say top i mean like... there should be less than 3 "top" ones)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah, I really don't know. Your system is different to the system in UK, Australia and Canada. We don't break mathematics up into sections like calculus and then apply a skill level to it. We apply a skill level to ALL of mathematics at particular points and you learn EVERYTHING at a particular level.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh... well what are the chances that i can attain a college grad level (in math) of mathematical understanding in the next year?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0given the rate that i covered calc 1 and 2 within 1.5 months

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'd say you're pretty good.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0College grad level in calculus...is that what you're asking?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You have to cover calculus of a complex variable as well. There's also tensor calculus.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0not just calculus, but all mathematics, can i attain that sort of knowledge, about 4 or more years of college math in the next 9 months?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0complex variable wont be too hard, what is tensor calc??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It *might* take a little longer ;p

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0They're devices we use to extend scalars, vectors and matrices to higher dimensions.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0my goal, i am currently 11 years behind

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It also depends on what areas you want to focus on in maths. There's discrete mathematics/number theory, mathematical logic, topology, algebra, mathematical statistics,...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah, I'be heard of him. I hope you get there (minus the autism).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0We 'know' general relativity is wrong  feel like fixing it, Arman?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Might be the first step.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nah, gibberish.... alright my chances of catching up to an ausbergers kid is highly unlikely, but i can at least try to match his pace...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think... idk. i will win .

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, that's the right attitude

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Just ace your doughnuts.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am becomeMyFan lol, got a new account because I got tired of my old name

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you like my new name LOL

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok. bit tired. should be doing my work but wasting time

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah, it's cool...did BMF die?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0LOL =D, or as sstarica says it, ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is oktalBlizzard meant to mean something?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0All that work you did collecting fans, gone!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well, it is just my internet user name/ nick name.Oktal means base 8, and blizzard is a natural disaster LOL, thanx I fanned you too, the 132nd fan

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0As in base 8 for numbers?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but now I am planning to help people more once I learn some more stuff and write my exams

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, for numbering system, like binary, octal, hexadecimal...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well, I wanted it to be a bit diferent then my usual nicks

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wow, you're probably the first person i've even asked that question who's said that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0:) but really it is great, because I made up my mind to enjoy maths and physics and stuff like this

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is all about the attitude, I think

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you assume, when you get to something in maths that you don't understand, that you can understand it eventually, well, the research says those people are more successful.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Took longer to say that than I had anticipated.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I just looked at my About me, and noticed something LOL, "...I have infinite interesting ideas but my limit is time..." coincidense but that actually reminds me of something I have learned in maths

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Should you be studying versus helping others?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well, I am actually solving questions my self, but once every hour or something I come here to solve a problem or two, to change the mental environment.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol, okay. you seem sorted.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sum_{\lim_{n \rightarrow \infty}}^{n} n\] where n is ideas something like this? can you improve it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You could just say\[\left \left\{ I_{oB} \right\} \right=\infty\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The cardinality (size) of the set of oktalBlizzard's ideas is infinite.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0too bad we can include maths symbols in about me text

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can refer people here to get a better idea.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so, have you checked out the new study groups? Physics, Chemistry and Computer Science?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I had a look at physics yesterday and I was the only one online

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I haven't looked at the others.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't know anything else about the other subjects. Well, enough to offer any advice.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Q: How does one insult a mathematician? A: You say: "Your brain is smaller than any ε > 0"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol, that's pretty good.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Theorem: Every positive integer is interesting. Proof: By contradiction, assume that there exists an uninteresting positive integer. Then there must be a smallest uninteresting positive integer. But that's pretty interesting! Therefore a contradiction!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Let epsilon be less than zero...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Are you coming up with this random stuff?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In some alley, a function meets up with a differential operator: "Get out of my way  or I'll differentiate you till you're zero!" "Try it  I'm \[e ^{x} \]..." "Too bad... I'm d/dy." no, I got this from a friend

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Pi had an argument with i. i told pi to be rational and pi told i to get real

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Nice! LOL, I think I heared something like that, Check this: Salary Theorem: The less you know, the more you make. Proof: Fact #1: Knowledge is Power Fact #2: Time is Money We know that: Power = Work / Time And since Knowledge = Power and Time = Money It is therefore true that Knowledge = Work / Money Solving for Money, we get: Money = Work / Knowledge Thus, as Knowledge approaches zero, Money approaches infinity, regardless of the amount of Work done

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah, I think that's more sadly true than funny ;p

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0aiight OB, I have to go. Have to do some work before the days runs out and I feel guilty ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0he also gave me this, but I dont get it at all, maybe you do: A SLICE OF PI ****************** 3.14159265358979 1640628620899 23172535940 881097566 5432664 09171 036 5 ok, bye, see you next time
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