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initial condition is (0,-2)

i think its a vertical asymptote which... definitely isint the point XD

You can then factor out y and rearrange into the form y=y(x).

brb

i got c=2?

.... -.-

ima try that, how about: y'=1+yy

dang, the small things get by me... that should be something like arctany=x+c? so tan(x+c)=y?

that explains why my condition is in radians

Yes.

alright... major confusion...
\[y'=(e ^{x-y})\div(1+e ^{x})\]

You want to solve that?

sadly ><

Just pull out the e^(-y) and it becomes separable ;)

asoghaqoeraifoiafauirfhlanihusdfvnnfldanufd

\[e^ydy=\frac{e^x}{1+e^x}dx\]

differential equations are gay -.-

lol

dont tell me any more!!!

tell you what? answers?

yeah.. dont tell me any more lol

no worries :D

I think you have the best icon...if that helps...

hahahaha it was annoyingly hard to make XD

it could be me, since i look like that

lol, how did your frigging doughnut go?

alright im stuck at e^y=ln(1+e^x)+c
initial condition is (0,1)

Is that y supposed to be y' (y-prime)?

nope, thats my solution

to the above equation

oh..

Yeah. You're right. Leave it like that too.

but i need to find c

Oh, just plug your numbers in.

\[e=\ln 2 +c \rightarrow c = e- \ln 2\]

any way to do that without a calc?

You mean simplify?

No.

What's wrong with Euler's number? :p

ah god its 1... can you check these real quick?

Check what?

Do you ever sleep?

not too much anymore lol

I need paper...I've run out...hang on...

but all my work is shown?

do i have to multiply the c by 2 aswell?

I'll do it here:

my answer doesnt make sense anyways... when i find y' its all weird and quotienty

\[\frac{dy}{dx}=xy^2 \rightarrow y^{-2}dy = x dx \rightarrow -y^{-1}=x+c\]

Your boundary condition is (0,-2), so

x+c or (1/2)xx+c?

\[-2^{-1}=0+c \rightarrow c=-\frac{1}{2}\]

So\[y^{-1}+x=\frac{1}{2} \rightarrow 2+2xy=y \rightarrow y(1-2x)=2 \rightarrow y=\frac{2}{1-2x}\]

waitttt the integral of xdx is (1/2)xx+c though!

Oh crap, I forgot the frigging x. Sorry Arman.

nah dont be sorry, i should hit the sheets tho, i'll probably have more questions tomorrow lol

I still get a different answer to you.

basic differential equations (like these) arent usually part of calc II are they?

different answer?

I'm not sure about the American system.

y=2/(1-x^2)

did you use (0,-2) for the initial whatever?

pellet, I wrote it wrong on my paper. I wrote (0,2). SORRY AGAIN :'(

NOW I get what you got.

>< nah man i hate when ppl tell me sorry

lol XD

thats probably better in the math world, where you need to be precise

Yeah, exactly.

is that prefered in college?

preferred*

given the rate that i covered calc 1 and 2 within 1.5 months

I'd say you're pretty good.

College grad level in calculus...is that what you're asking?

You have to cover calculus of a complex variable as well. There's also tensor calculus.

complex variable wont be too hard, what is tensor calc??

It *might* take a little longer ;p

They're devices we use to extend scalars, vectors and matrices to higher dimensions.

They're very useful.

my goal, i am currently 11 years behind

Yeah, I'be heard of him. I hope you get there (minus the autism).

*I've*

We 'know' general relativity is wrong - feel like fixing it, Arman?

sounds like a plan

What about bed?

Might be the first step.

oiudhvcapoufimnac

Is that code?

fine -.-

lol

i think... idk. i will win -.-

yeah, that's the right attitude

Just ace your doughnuts.

lol iight gnight yo

nite

hey arman

I am becomeMyFan lol, got a new account because I got tired of my old name

hey loki=D

hello

how are you doin?

do you like my new name LOL

ok. bit tired. should be doing my work but wasting time

Yeah, it's cool...did BMF die?

yeah

sad

RIP, BMF

LOL =D, or as sstarica says it, ^_^

Is oktalBlizzard meant to mean something?

i just fanned you

All that work you did collecting fans, gone!

=D yeah

As in base 8 for numbers?

but now I am planning to help people more once I learn some more stuff and write my exams

yes, for numbering system, like binary, octal, hexadecimal...

Cool.../random

well, I wanted it to be a bit diferent then my usual nicks

Arman's gone to bed

:)

How's the studying?

great

wow, you're probably the first person i've even asked that question who's said that

:) but really it is great, because I made up my mind to enjoy maths and physics and stuff like this

it is all about the attitude, I think

lol

it is

research backs it

Took longer to say that than I had anticipated.

Remains of the day.

lol

Should you be studying versus helping others?

lol, okay. you seem sorted.

You could just say\[\left| \left\{ I_{oB} \right\} \right|=\infty\]

The cardinality (size) of the set of oktalBlizzard's ideas is infinite.

:) nice

too bad we can include maths symbols in about me text

You can refer people here to get a better idea.

=D

so, have you checked out the new study groups? Physics, Chemistry and Computer Science?

I had a look at physics yesterday and I was the only one online

me too

I haven't looked at the others.

I don't know anything else about the other subjects. Well, enough to offer any advice.

Q: How does one insult a mathematician?
A: You say: "Your brain is smaller than any ε > 0"

lol, that's pretty good.

Let epsilon be less than zero...

Are you coming up with this random stuff?

I have one.

Pi had an argument with i.
i told pi to be rational and
pi told i to get real

Yeah, I think that's more sadly true than funny ;p

aiight OB, I have to go. Have to do some work before the days runs out and I feel guilty ;)

hehe..see you :)

lolol