anonymous
  • anonymous
I need some help with questions 5-10 http://locker.palcs.org/~jbaskwill/pc/5-3practice.PDF
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
It has to do with Sum and Difference Identities in Pre-Calc
anonymous
  • anonymous
no 5 -> we know that cosx cosy+sinx siny = cos(x-y) therefore cos133 cos58+ sin133 sin58 = cos(133-58) = cos75 the answer is B
anonymous
  • anonymous
6) sinx cosy +cosx siny = sin(x+y) sin(π/5) cos(π/11) +sin(π/11) cos(π/5) = sin(π/5 + π/11) = sin(16π/55) answer : D

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
7) (tanx - tany)/(1+tanx tany) = tan(x-y) so the answer is tan 48
anonymous
  • anonymous
thank you soo much. you helped a lot!
anonymous
  • anonymous
you're welcome, sorry i can't help for number 8-10
anonymous
  • anonymous
its ok
dumbcow
  • dumbcow
i can help with 9 and 10, you need to use the sum and difference formulas 9) Notice its a sin function because it crosses the x-axis around x=2 meaning the sin function has been shifted to the right 2 units. Now use y = sin(x+(-2)) = sin(x)cos(-2) +cos(x)sin(-2) 10) This one is a cosine function because at x=3 it starts a new period at 1 so the cosine function has been shifted right 3 units. So y = cos(x+(-3)) = cos(x)cos(-3) - sin(x)sin(-3)
anonymous
  • anonymous
thank you

Looking for something else?

Not the answer you are looking for? Search for more explanations.