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anonymous

  • 5 years ago

5y(-y^2-7y)

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  1. anonymous
    • 5 years ago
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    \[5y(-2y ^{2}-7y)\]

  2. amistre64
    • 5 years ago
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    so what do you know to do to this problem?

  3. anonymous
    • 5 years ago
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    i dont know how to do these types of problems im home sick today and this is the practice problems the teacher wants me to do to turn in tomorow to see if i need to do the assighnment or not

  4. amistre64
    • 5 years ago
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    ok... lets review some basic concepts then ok.

  5. amistre64
    • 5 years ago
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    to make it easier, lets do this: 3(8) = 24 right?

  6. anonymous
    • 5 years ago
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    yeah

  7. amistre64
    • 5 years ago
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    then this should also equal 24: 3(6+2) = 24 ...make sense?

  8. anonymous
    • 5 years ago
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    yeah

  9. amistre64
    • 5 years ago
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    good, now how do we prove this? we "distibute" that 3 thru the (6+2) like this, just multiply it thru... 3(6) + 3(2) = 24 18 + 6 = 24 24 = 24.... Do you see how I did that?

  10. amistre64
    • 5 years ago
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    distribute is the word I was trying to type :)

  11. anonymous
    • 5 years ago
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    yeah so if i do that for this problem i end up with -45y^{2} would that be correct

  12. anonymous
    • 5 years ago
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    -45y squared

  13. amistre64
    • 5 years ago
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    not yet, there are a few more things to iron out...

  14. amistre64
    • 5 years ago
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    you see the "y"'s in there....they play by the same rules, but with a difference result

  15. anonymous
    • 5 years ago
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    so it would be just -45?

  16. amistre64
    • 5 years ago
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    quit trying to jump ahead of the curve, if you simply want ananswer to it it aint gonna be useful to you..... we will get to the answer soon enough :)

  17. amistre64
    • 5 years ago
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    do you know how the rules of positive and negatives work with multiplication? (+)(+) = (+) (-)(-)=(+) (-)(+)=(-) do you know these rules?

  18. anonymous
    • 5 years ago
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    yes

  19. amistre64
    • 5 years ago
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    good, then the only thing left to do is to figure out what to do with they "y"s :)

  20. amistre64
    • 5 years ago
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    y^2 means that you have 2 little y's that have been pushed together like this: yy = y^2 y^5 means 5 little y's are pushed together like this: yyyyy = y^5 does that make sense?

  21. anonymous
    • 5 years ago
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    yeah

  22. amistre64
    • 5 years ago
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    good, when we multiply these y's together, we simply add up all the little y's together, for example: y^2 times y^5 = yy yyyyy = yyyyyyy = y^7 y^1 times y^3 means y yyy = yyyy = y^4 does that make sense?

  23. anonymous
    • 5 years ago
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    yea

  24. amistre64
    • 5 years ago
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    then lets step thru your problem and use this understanding to get the answer :) ok?

  25. anonymous
    • 5 years ago
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    ok

  26. amistre64
    • 5 years ago
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    5y(-y^2-7y) lets distribute that 5 thru to get: 5(-y^2) + 5(-7y) = (-10y^2 -35y) now were left with that y on the outside to distribute thru like this: y(-10y^2 -35y) y(-10y^2) + y(-35y) -10yyy + -35yy = -10y^3 -35y^2 and thats as far as we can take it

  27. amistre64
    • 5 years ago
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    and I messed it up lol.....

  28. amistre64
    • 5 years ago
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    5(-y^2) = -5y^2...

  29. amistre64
    • 5 years ago
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    copy edit repaste...

  30. amistre64
    • 5 years ago
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    5y(-y^2-7y) lets distribute that 5 thru to get: 5(-y^2) + 5(-7y) = (-5y^2 -35y) now were left with that y on the outside to distribute thru like this: y(-5y^2 -35y) y(-5y^2) + y(-35y) -5yyy + -35yy = -5y^3 -35y^2 and thats as far as we can take it

  31. anonymous
    • 5 years ago
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    so then the answer would be -5y^3-35y^2?

  32. amistre64
    • 5 years ago
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    yep, thats the answer

  33. anonymous
    • 5 years ago
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    oh ok thanks

  34. amistre64
    • 5 years ago
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    youre welcome

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