5y(-y^2-7y)

- anonymous

5y(-y^2-7y)

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- anonymous

\[5y(-2y ^{2}-7y)\]

- amistre64

so what do you know to do to this problem?

- anonymous

i dont know how to do these types of problems im home sick today and this is the practice problems the teacher wants me to do to turn in tomorow to see if i need to do the assighnment or not

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## More answers

- amistre64

ok... lets review some basic concepts then ok.

- amistre64

to make it easier, lets do this:
3(8) = 24 right?

- anonymous

yeah

- amistre64

then this should also equal 24:
3(6+2) = 24 ...make sense?

- anonymous

yeah

- amistre64

good, now how do we prove this? we "distibute" that 3 thru the (6+2) like this, just multiply it thru...
3(6) + 3(2) = 24
18 + 6 = 24
24 = 24....
Do you see how I did that?

- amistre64

distribute is the word I was trying to type :)

- anonymous

yeah so if i do that for this problem i end up with -45y^{2} would that be correct

- anonymous

-45y squared

- amistre64

not yet, there are a few more things to iron out...

- amistre64

you see the "y"'s in there....they play by the same rules, but with a difference result

- anonymous

so it would be just -45?

- amistre64

quit trying to jump ahead of the curve, if you simply want ananswer to it it aint gonna be useful to you..... we will get to the answer soon enough :)

- amistre64

do you know how the rules of positive and negatives work with multiplication?
(+)(+) = (+)
(-)(-)=(+)
(-)(+)=(-)
do you know these rules?

- anonymous

yes

- amistre64

good, then the only thing left to do is to figure out what to do with they "y"s :)

- amistre64

y^2 means that you have 2 little y's that have been pushed together like this:
yy = y^2
y^5 means 5 little y's are pushed together like this:
yyyyy = y^5
does that make sense?

- anonymous

yeah

- amistre64

good, when we multiply these y's together, we simply add up all the little y's together, for example:
y^2 times y^5 = yy yyyyy = yyyyyyy = y^7
y^1 times y^3 means y yyy = yyyy = y^4
does that make sense?

- anonymous

yea

- amistre64

then lets step thru your problem and use this understanding to get the answer :) ok?

- anonymous

ok

- amistre64

5y(-y^2-7y) lets distribute that 5 thru to get:
5(-y^2) + 5(-7y) = (-10y^2 -35y)
now were left with that y on the outside to distribute thru like this:
y(-10y^2 -35y)
y(-10y^2) + y(-35y)
-10yyy + -35yy = -10y^3 -35y^2 and thats as far as we can take it

- amistre64

and I messed it up lol.....

- amistre64

5(-y^2) = -5y^2...

- amistre64

copy edit repaste...

- amistre64

5y(-y^2-7y) lets distribute that 5 thru to get:
5(-y^2) + 5(-7y) = (-5y^2 -35y)
now were left with that y on the outside to distribute thru like this:
y(-5y^2 -35y)
y(-5y^2) + y(-35y)
-5yyy + -35yy = -5y^3 -35y^2 and thats as far as we can take it

- anonymous

so then the answer would be -5y^3-35y^2?

- amistre64

yep, thats the answer

- anonymous

oh ok thanks

- amistre64

youre welcome

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